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我試圖使用外部函數獲取3D表面。並且我定義的函數在data.frame中引用列。以下是可重現的簡要代碼。使用函數包括數據幀引用的外部函數錯誤
的test.txt是
a b c
1 0 0
2 0 0
3 0 0
6 0 0
4 0 0
和代碼顯示爲錯誤
test<- read.table(file="test.txt",header=TRUE)
testf<-function(q,w){
test$b<-q
test$c<-w
sum(test$b)+sum(test$c)
}
x<-seq(1,10,by = 1)
y<-seq(0,30,by = 1)
z<-outer(x,y,testf)
結果是
Error in `$<-.data.frame`(`*tmp*`, "b", value = c(1, 2, 3, 4, 5, 6, 7, :
replacement has 310 rows, data has 5
5.stop(sprintf(ngettext(N, "replacement has %d row, data has %d",
"replacement has %d rows, data has %d"), N, nrows), domain = NA)
4.`$<-.data.frame`(`*tmp*`, "b", value = c(1, 2, 3, 4, 5, 6, 7,
8, 9, 10, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1, 2, 3, 4, 5, 6, 7,
8, 9, 10, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1, 2, 3, 4, 5, 6, 7,
8, 9, 10, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1, 2, 3, 4, 5, 6, 7, ...
3.`$<-`(`*tmp*`, "b", value = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10,
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10,
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10,
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, ...
2. FUN(X, Y, ...)
1. outer(x, y, testf)
功能本身似乎因爲testf(1,1)的作品沒有問題
> testf(1,1)
[1] 10
任何意見將不勝感激!
test'你定義了'5'行,但你想用'10'行數字矢量替換它的data.frame'的方式。這正是你想要做的嗎?因爲行數應該相等。 – SirSaleh
是的,我要做的是獲取每個用戶定義的函數結果,這是通過更改列數據基於數據幀計算出來的(在實際代碼中,我使用MAPLLY從數據框列中獲取輸入數據)。只有LOOP才能獲得z軸結果? –
或者還有其他的功能與外部功能類似嗎? –