我正在研究生成大型ODT文件的應用程序。應用程序將XML寫入content.xml,styles.xml等。我試圖在表格中獲取一些簡單的表格樣式,並且在生成文件後,我可以驗證它是否都通過XML端進行驗證我期望它,但是當我在文字處理器中打開文件時,沒有任何樣式實際顯示。我已經把它分解成只是試圖讓簡單的表格顯示一些樣式,甚至根本不工作。XML中的ODT表格樣式不起作用
在「自動樣式」標籤中,我有這個樣式片段。
<style:style style:name="mytable" style:family="table">
<style:properties
fo:background-color="#666666"
style:width="445.5pt"
fo:margin-left="4.5pt"
fo:margin-top="0pt"
fo:margin-bottom="0pt"
table:align="left"
/>
</style:style>
<style:style style:name="mytable.A" style:family="table-column">
<style:properties fo:background-color="#000000" style:column-width="117pt"/>
</style:style>
<style:style style:name="mytable.B" style:family="table-column">
<style:properties style:column-width="103.5pt"/>
</style:style>
<style:style style:name="mytable.C" style:family="table-column">
<style:properties style:column-width="193.5pt"/>
</style:style>
<style:style style:name="mytable.D" style:family="table-column">
<style:properties style:column-width="31.5pt"/>
</style:style>
編輯:這是我的活文檔的屏幕截圖。這是來自這個確切文檔的content.xml部分,上面發佈的樣式是相同的。
<table:table table:name="mytable" table:style-name="mytable">
<table:table-columns>
<table:table-column table:style-name="mytable.A"/>
<table:table-column table:style-name="mytable.B"/>
<table:table-column table:style-name="mytable.C"/>
<table:table-column table:style-name="mytable.D"/>
</table:table-columns>
<table:table-header-rows>
<table:table-row>
<table:table-cell table:style-name="mytable.A1" office:value-type="string">
<text:p text:style-name="P39">citation</text:p>
</table:table-cell>
<table:table-cell table:style-name="mytable.B1" office:value-type="string">
<text:p text:style-name="P39">title</text:p>
</table:table-cell>
<table:table-cell table:style-name="mytable.C1" office:value-type="string">
<text:p text:style-name="P39">description</text:p>
</table:table-cell>
<table:table-cell table:style-name="mytable.D1" office:value-type="string">
<text:p p text:style-name="P38"/>
</table:table-cell>
</table:table-row>
</table:table-header-rows>
<table:table-row>
<table:table-cell table:style-name="mytable.A2" office:value-type="string">
<text:p p text:style-name="P39">Administrative Safe-guards</text:p>
</table:table-cell>
<table:table-cell table:style-name="mytable.B2" office:value-type="string">
<text:p p text:style-name="P39"/>
</table:table-cell>
<table:table-cell table:style-name="mytable.C2" office:value-type="string">
<text:p p text:style-name="P39"/>
</table:table-cell>
<table:table-cell table:style-name="mytable.D2" office:value-type="string">
<text:p p text:style-name="P38"/>
</table:table-cell>
</table:table-row>
</table:table>
你能發佈什麼樣的表看起來像在作家的屏幕截圖? –
我在編輯以及content.xml中添加了一個屏幕截圖 – user2303120