類型錯誤：列表索引必須是整數，而不是str的

Question

使用的變量的聲明如下：

self.features = {}  #dictionary defined for storing the features and the values 
self.featureNameList = [] #list to store the names and values of the features 
self.featureCounts = collections.defaultdict(lambda: 1) #the counts of the features and labels 
self.featureVectors = [] # 
self.labelCounts = collections.defaultdict(lambda: 0)    
def Classify(self):  #featureVector is a simple list like the ones that we use to train 
    probabilityPerLabel = {} 
    for label in self.labelCounts.keys(): 
     Prob = 0 
     for featureValue in self.featureVectors: 
      #print self.labelCounts[label] 
      Prob+=self.featureCounts[[label][self.featureNameList[self.featureVectors.index(featureValue)]][featureValue]]/self.labelCounts[label] 
      # Prob+= self.featureCounts(label, self.featureNameList[self.featureVectors.index(featureValue)], featureValue)/self.labelCounts[label] 
     probabilityPerLabel[label] = (self.labelCounts[label]/sum(self.labelCounts.values())) * (Prob) 
    print probabilityPerLabel 
    return max(probabilityPerLabel, key = lambda classLabel: probabilityPerLabel[classLabel]) 

的錯誤是在生產線生產：

Prob+=self.featureCounts[[label][self.featureNameList[self.featureVectors.index(featureValue)]][featureValue]]/self.labelCounts[label] 

Answer 1

你的問題可能是：

[label][self.featureNameList[self.featureVectors.index(featureValue)] 

它是什麼樣子讓我看到你正在長度爲1的列表：

[label] 

然後你想通過索引從它那裏得到一個元素：

[self.featureNameList[self.featureVectors.index(featureValue)] 

但外括號內的東西，計算結果爲一個字符串。並且字符串不能用於索引列表。

最終，這幾乎可以肯定是而不是你正在嘗試做什麼，但我認爲它解釋了錯誤。一般來說，我會建議你避免使用這種長時間混淆的1-liners，並使用臨時（但恰當命名）的變量將其分解爲它的組成部分。這將使您的代碼更易於理解，因此編寫和開發起來會更容易。