爲什麼不是第二個功能工作？

Question

我想做一個小遊戲，但我沒有很多經驗。此外，我知道這可能是絕對不能做的最好辦法，因此，如果任何人有什麼適合初學者那簡直太好了

<a id="key">There is a key on the floor</a> 
<button onclick="keylol()">Pick it up</button> 

<a id="door">You see a locked door</a> 
<button onclick="doortext()">Try to open the door</button> 

<script> 
var key = 1 
function keylol() { 
document.getElementById("key").innerHTML = "You picked up the key"; 
var key = 2; 
} 

function doortext() { 
if (key = 1) { 
document.getElementById("door").innerHTML = "You cannot open a locked door"; 
} else { 
document.getElementById("door").innerHTML = "You opened the door hooray"; 
} 
} 
</script> 

Answer 1

您需要使用===而非=：

if (key === 1) { 
    ... 
} 

Answer 2

你讓兩個錯誤：

第一個是，你重新聲明一個在keylol功能的範圍內命名key新的變量，因此價值2不是屁股與外部變量key對齊。

第二個是，您將重新聲明key變量，而不是在if子句中比較它。

變化var key = 2到key = 2和if(key = 1)到if(key === 1)：

var key = 1 
 

 
function keylol() { 
 
    document.getElementById("key").innerHTML = "You picked up the key"; 
 
    key = 2; 
 
} 
 

 
function doortext() { 
 
    if (key === 1) { 
 
    document.getElementById("door").innerHTML = "You cannot open a locked door"; 
 
    } else { 
 
    document.getElementById("door").innerHTML = "You opened the door hooray"; 
 
    } 
 
}

<a id="key">There is a key on the floor</a> 
 
<button onclick="keylol()">Pick it up</button> 
 

 
<a id="door">You see a locked door</a> 
 
<button onclick="doortext()">Try to open the door</button>

Answer 3

<a id="key">There is a key on the floor</a> 
 
<button onclick="keylol()">Pick it up</button> 
 

 
<a id="door">You see a locked door</a> 
 
<button onclick="doortext()">Try to open the door</button> 
 

 
<script> 
 
var key = 1 
 
function keylol() { 
 
document.getElementById("key").innerHTML = "You picked up the key"; 
 
key = 2; 
 
} 
 

 
function doortext() { 
 
if (key == 1) { 
 
document.getElementById("door").innerHTML = "You cannot open a locked door"; 
 
} else { 
 
document.getElementById("door").innerHTML = "You opened the door hooray"; 
 
} 
 
} 
 
</script>