無法獲得循環打印出偶數高達237

Question

//Loop through and print out all even numbers from the numbers list in the same order 
//they are received. Don't print any numbers that come after 237 in the sequence. 
public class excercise4 { 

    public static void main(String[] args) { 
     int[] numbers = { 
      951, 402, 984, 651, 360, 69, 408, 319, 601, 485, 980, 507, 725, 547, 544, 
      615, 83, 165, 141, 501, 263, 617, 865, 575, 219, 390, 984, 592, 236, 105, 942, 941, 
      386, 462, 47, 418, 907, 344, 236, 375, 823, 566, 597, 978, 328, 615, 953, 345, 
      399, 162, 758, 219, 918, 237, 412, 566, 826, 248, 866, 950, 626, 949, 687, 217, 
      815, 67, 104, 58, 512, 24, 892, 894, 767, 553, 81, 379, 843, 831, 445, 742, 717, 
      958, 609, 842, 451, 688, 753, 854, 685, 93, 857, 440, 380, 126, 721, 328, 753, 470, 
      743, 527}; 


     for (int i=0; i < numbers.length; i++) { 


      int el = numbers[i]; 
      if (el >= 237) break; 
      if (el%2==0)   // using the remainder operator % 
      System.out.print(el+" "); // the Expected Output likes it like this! 
     } 
    } 
} 

Answer 1

而是具有：

if (el >= 237) break; 

有：

if (el >= 237) continue; 

Answer 2

你可能想改變這一行：

if (el >= 237) break; 

這一個

if (el >= 237) continue; 

因爲break句子會從整個循環中出去。而continue將轉到下一個陣列元素。