-3
我想做一個簡單的職位到Facebook,我有同樣的樣本做一個郵政編碼,我改變了一點。有沒有辦法做一個職位在PHP
我收到以下錯誤
解析錯誤:語法錯誤,意外 ';'在上線/home/consult/public_html/projects/facebook/index.php 13
線是
'access_token'=>;urlencode($code),
的代碼:
<?php
//set POST variables
$url = 'https://graph.facebook.com/arjun/feed';
$code="testing";
$message="Test";
$fields = array(
'access_token'=>;urlencode($code),
'message'=>;urlencode($message),
);
//url-ify the data for the POST
foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&'; }
rtrim($fields_string,'&');
//open connection
$ch = curl_init();
//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_POST,count($fields));
curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string);
//execute post
// $result = curl_exec($ch);
//close connection
curl_close($ch);
?>
+1,爲察覺這一點。 –
@DarinDimitrov:沒有那麼難,即使在那個混亂中 – genesis
@genesisφ爲什麼不幫助他通過**指出所有的錯誤**? – salathe