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我有一個表格,將數據插入數據庫。其中一個字段是weDate
這與PHP mysql_query()手動輸入日期的作品PHP變量不
$weDate=date('Y-m-d',strtotime('Friday'))
填寫如果我使用以下命令:
$sql = mysql_query("SELECT ID as 'DB_ID',
partnumber as 'Part_Number',
pndesc as 'Part Number Description',
name as 'Name',
reason as 'Reason',
comment as 'Comments',
date as 'Date',
time as 'Time',
weDate as 'Weekend Date'
FROM $table
WHERE weDate = '2013-05-03'");
我得到的返回結果。
當我嘗試:
$sql = mysql_query("SELECT ID as 'DB_ID',
partnumber as 'Part_Number',
pndesc as 'Part Number Description',
name as 'Name',
reason as 'Reason',
comment as 'Comments',
date as 'Date',
time as 'Time',
weDate as 'Weekend Date'
FROM $table
WHERE weDate = '$weDate2'");
我得不到任何回報。爲什麼?
的PHP變量是:
$weDate2 = date('Y-m-d', strtotime('-1 weeks Friday')
[**請不要在新代碼中使用'mysql_ *'函數**](http://bit.ly/phpmsql)。他們不再被維護[並且被正式棄用](http://j.mp/XqV7Lp)。看到[**紅框**](http://j.mp/Te9zIL)?學習[*準備的語句*](http://j.mp/T9hLWi),並使用[PDO](http://php.net/pdo)或[MySQLi](http://php.net/ mysqli) - [這篇文章](http://j.mp/QEx8IB)將幫助你決定哪個。如果你選擇PDO,[這裏是一個很好的教程](http://j.mp/PoWehJ)。 – Kermit 2013-05-06 19:00:00
您指的是哪個星期五?如果你運行'date('Y-m-d',strtotime('Friday'))',你會得到'2013-05-10'。 – Terry 2013-05-06 19:00:12
您是否嘗試回顯$ weDate2以查看實際輸出的內容?我敢打賭,問題在於它實際上在輸出什麼,而不是你期望它輸出什麼。 – 2013-05-06 19:01:01