完整性約束違規：1052列和where子句是曖昧

Question

我有兩個表的Tbl_payroll_leave_employeev2和tbl_payroll_leave_schedulev2，我想join他們，但即時得到類似這樣的錯誤

「SQLSTATE [23000]：完整性約束違規：1052列 'payroll_leave_employee_id' 在where子句是不明確的（SQL：選擇payroll_employee_id從tbl_payroll_leave_employee_v2內上tbl_payroll_leave_employee_v2加入tbl_payroll_leave_schedulev2payroll_leave_employee_id = tbl_payroll_leave_schedulev2payroll_leave_employee_id其中payroll_leave_employee_id = 5。）◀」

我的表結構

$employee_id = Tbl_payroll_leave_employeev2::select('payroll_employee_id') 
    ->join('tbl_payroll_leave_schedulev2','tbl_payroll_leave_employee_v2.payroll_leave_employee_id','=','tbl_payroll_leave_schedulev2.payroll_leave_employee_id') 
    ->where('payroll_leave_employee_id',$emp) 
    ->get(); 

Answer 1

在情況下，你必須定義表tbl_payroll_leave_employee_v2或表的字段payroll_leave_employee_idtbl_payroll_leave_schedulev2

$employee_id = Tbl_payroll_leave_employeev2::select('payroll_employee_id') ->join('tbl_payroll_leave_schedulev2','tbl_payroll_leave_employee_v2.payroll_leave_employee_id','=','tbl_payroll_leave_schedulev2.payroll_leave_employee_id') ->where('tbl_payroll_leave_schedulev2.payroll_leave_employee_id',$emp) ->get();