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這是我的代碼(可怕的):數據(無法弄清楚如何做到佈局)
<?php
include 'connect/con.php';
$result = mysqli_query($con,"SELECT id, vidTitle FROM newsvid");
$result1 = mysqli_query($con,"SELECT imgCover, vidSD FROM newsvid");
$result2 = mysqli_query($con,"SELECT published FROM newsvid");
echo "<table width=\"600\" border=\"1\"><tbody>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo '<td width=\"10%\"><a href="details.php?id='.$row['id'].'">'.$row['id'].'</a></td>';
echo "<td width=\"90%\">" . $row['vidTitle'] . "</td>";
echo "</tr>";
}
echo "</tbody></table>";
echo "<table width=\"600\" border=\"1\"><tbody>";
while($row = mysqli_fetch_array($result1)) {
echo "<tr>";
echo "<td width=\"40%\">" . $row['imgCover'] . "</td>";
echo "<td width=\"60%\">" . $row['vidSD'] . "</td>";
echo "</tr>";
}
echo "</tbody></table>";
echo "<table width=\"600\" border=\"1\"><tbody>";
while($row = mysqli_fetch_array($result2)) {
echo "<tr>";
echo "<td >" . $row['published'] . "</td>";
echo "</tr>";
}
echo "</tbody></table>";
mysqli_close($con);
?>
</body>
</html>
的問題是如何顯示從數據庫中的數據在此佈局:
--------------------------------
-id----------vidTitle-----------
--------------------------------
-imgCover------vidSD------------
--------------------------------
----------published-------------
所以每次我會添加更多的數據,就像我的另一個塊顯示前將現有的一個下積少成多。 ................................................. .......................................
EVERYTHING看起來很酷但是在表格寬度10%和另一個TR中td 40%不起作用的主要問題((( – Denis 2014-10-22 01:16:11
)所有表格看起來都像50%50%,如果更改爲10 %由90%沒有改變,他們仍然是相同的.. – Denis 2014-10-22 01:22:56