顯示在MySQL中含有相同值的所有行

Question

我有一個MySQL數據庫：

ID | Name 
1 | Bob 
2 | James 
3 | Jack 
4 | Bob 
5 | James 

如何將返回所有列的列表，其中相同的名字出現不止一次，例如，我會要退貨：

1 | Bob 
2 | James 
4 | Bob 
5 | James 

我寫了一個數查詢：

SELECT Name, COUNT(Name) 
AS NumOccurrences 
FROM table 
GROUP BY Name 
HAVING (COUNT(Name) > 1) 

但這只是返回是這樣的：

Bob | 2 
James | 2 

而我想返回完整的行返回。

任何幫助將不勝感激，謝謝。

Answer 1

試試這個SQL查詢：

select distinct a.name, a.id 
from table a, table b 
where a.name = b.name and a.id != b.id 

Answer 2

你可以用一個子做選擇

SELECT * FROM table WHERE Name IN (
    SELECT Name FROM table GROUP BY Name HAVING count(*) > 1 
) 

此外，如果你的區別匹配是多列，您可以用笛卡爾集：

SELECT * FROM table WHERE (firstName, lastName) IN (
    SELECT firstName, lastName FROM table GROUP BY firstName, lastName HAVING count(*) > 1 
) 

Answer 3

試試這個

SELECT Name, COUNT(Name) AS NumOccurrences 
FROM table 
GROUP BY Name 
HAVING COUNT(*) > 0