2013-07-29 43 views
1

我正在用Spring和Hibernate一個Java web應用程序,但是當我執行它,我有這樣的錯誤:顯示java.lang.NullPointerException由於sessionFactory.getCurrentSession()

SEVERE: El Servlet.service() para el servlet [springapp] en el contexto con ruta [/appCracks] lanzó la excepción [Request processing failed; nested exception is java.lang.NullPointerException] con causa raíz 
java.lang.NullPointerException 
    at com.companyname.springapp.repository.UsuarioDaoImp.getTodosUsuariosList(UsuarioDaoImp.java:26) 
    at com.companyname.springapp.service.SimpleAnonimoManager.identificarse(SimpleAnonimoManager.java:21) 
    at com.companyname.springapp.web.IdentificarseFormController.onSubmit(IdentificarseFormController.java:46) 
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) 
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) 
    at java.lang.reflect.Method.invoke(Unknown Source) 
    at org.springframework.web.bind.annotation.support.HandlerMethodInvoker.invokeHandlerMethod(HandlerMethodInvoker.java:174) 
    at org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter.invokeHandlerMethod(AnnotationMethodHandlerAdapter.java:421) 
    at org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter.handle(AnnotationMethodHandlerAdapter.java:409) 
    at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:771) 
    at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:716) 
    at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:644) 
    at org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:560) 
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:647) 
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:728) 
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305) 
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210) 
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:222) 
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123) 
    at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:472) 
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171) 
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:99) 
    at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:936) 
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118) 
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:407) 
    at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1004) 
    at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:589) 
    at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:312) 
    at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source) 
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source) 
    at java.lang.Thread.run(Unknown Source) 

的錯誤是在這行,當我嘗試獲取會話:

UsuarioDaoImp.java

01:

return this.sessionFactory.getCurrentSession().createQuery("from Usuario u order by u.id").list(); 

我複製到這裏,參與了該錯誤的類

package com.companyname.springapp.repository; 

import java.util.List; 

import javax.persistence.EntityManager; 
import javax.persistence.PersistenceContext; 

import org.hibernate.SessionFactory; 
import org.springframework.stereotype.Repository; 
import org.springframework.transaction.annotation.Transactional; 

import com.companyname.springapp.domain.Usuario; 

@Repository(value = "usuarioDao") 
public class UsuarioDaoImp implements UsuarioDao { 

    private SessionFactory sessionFactory; 

    public void setSessionFactory(SessionFactory sessionFactory) { 
     this.sessionFactory = sessionFactory; 
    } 

    @Override 
    @SuppressWarnings("unchecked") 
    public List<Usuario> getTodosUsuariosList() { 
     return this.sessionFactory.getCurrentSession() 
       .createQuery("from Usuario u order by u.id") 
       .list(); 
    } 

    @Override 
    public String encriptarContrasena(String contrasena) { 
     return (String) this.sessionFactory.getCurrentSession() 
       .createQuery("select SHA1(:c)") 
       .setParameter ("c", contrasena) 
       .uniqueResult(); 
    } 

    @Override 
    public String getTipoUsuario(String usuario) { 
     return (String) this.sessionFactory.getCurrentSession() 
       .createQuery("select u.tipoUsuario from Usuario u where u.usuario = '" + 
       usuario + "'") 
       .uniqueResult(); 
    } 


} 

SimpleAnonimoManager.java:

package com.companyname.springapp.service; 

import java.util.List; 

import org.springframework.beans.factory.annotation.Autowired; 
import org.springframework.stereotype.Component; 

import com.companyname.springapp.domain.Usuario; 
import com.companyname.springapp.repository.UsuarioDao; 

@Component 
public class SimpleAnonimoManager implements AnonimoManager { 

    private static final long serialVersionUID = 1L; 

    @Autowired 
    private UsuarioDao usuarioDao; 

    @Override 
    public boolean identificarse(String nombreUsuario, String contrasena) { 
     List<Usuario> usuarios = usuarioDao.getTodosUsuariosList(); 
     if (usuarios != null) { 
      for (Usuario usuario : usuarios) { 
       if (usuario.getUsuario().equals(nombreUsuario)) { 
        if (usuario.getContrasena().equals(usuarioDao.encriptarContrasena(contrasena))) { 
         return true; 
        } 
        else { 
         return false; 
        } 
       } 
      } 
     } 
     return false; 
    } 

    @Override 
    public String getTipoUsuario(String usuario) { 
     return usuarioDao.getTipoUsuario(usuario); 
    } 

} 

IdentificarseFormController.java:

package com.companyname.springapp.web; 

import java.util.Calendar; 

import org.hibernate.SessionFactory; 
import org.springframework.beans.factory.annotation.Autowired; 
import org.springframework.stereotype.Controller; 
import org.springframework.validation.BindingResult; 
import org.springframework.web.bind.annotation.RequestMapping; 
import org.springframework.web.bind.annotation.RequestMethod; 
import org.springframework.web.servlet.ModelAndView; 
import org.springframework.web.servlet.view.RedirectView; 

import javax.servlet.ServletException; 
import javax.servlet.http.HttpServletRequest; 
import javax.servlet.http.HttpServletResponse; 
import javax.validation.Valid; 

import com.companyname.springapp.service.AdminManager; 
import com.companyname.springapp.service.GmcracksManager; 
import com.companyname.springapp.service.Identificarse; 
import com.companyname.springapp.service.AnonimoManager; 

@Controller 
@RequestMapping(value="/identificarse.htm") 
public class IdentificarseFormController { 

    @Autowired 
    private AnonimoManager anonimoManager; 

    @RequestMapping(method = RequestMethod.POST) 
    public ModelAndView onSubmit(HttpServletRequest request, HttpServletResponse response, @Valid Identificarse identificarse, BindingResult result) { 

     String usuario = identificarse.getUsuario(); 
     String contrasena = identificarse.getContrasena(); 

     boolean IdentificacionOK = anonimoManager.identificarse(usuario, contrasena); 

     if (IdentificacionOK) { 
      request.getSession().setAttribute("nombreUsuario", usuario); 
      String tipoUsuario = anonimoManager.getTipoUsuario(usuario); 
      request.getSession().setAttribute("tipoUsuario", tipoUsuario); 
      return new ModelAndView (new RedirectView("hello.htm")); 
     } 
     else { 
      request.getSession().setAttribute("error", "Usuario o contraseña incorrectos"); 
      return new ModelAndView (new RedirectView ("identificarse.htm")); 
     } 
    } 

    @RequestMapping(method = RequestMethod.GET) 
    protected Identificarse formBackingObject(HttpServletRequest request) throws ServletException { 
     Identificarse identificarse = new Identificarse(); 
     return identificarse; 
    } 

的配置文件是這樣的: APP-config.xml中

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:mvc="http://www.springframework.org/schema/mvc" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd 
     http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd 
     http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> 

    <bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource"> 
     <property name="basename" value="messages"/> 
    </bean> 

    <!-- Scans the classpath of this application for @Components to deploy as beans --> 
    <context:component-scan base-package="com.companyname.springapp.web" /> 

    <!-- Configures the @Controller programming model --> 
    <mvc:annotation-driven/> 

    <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
     <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> 
     <property name="prefix" value="/jsp/"></property> 
     <property name="suffix" value=".jsp"></property>   
    </bean> 

</beans> 

applicationContext.xml中:

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xmlns:p="http://www.springframework.org/schema/p" 
    xmlns:tx="http://www.springframework.org/schema/tx" 
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd 
     http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd 
     http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> 


    <!-- holding properties for database connectivity /--> 
    <context:property-placeholder location="classpath:jdbc.properties"/> 

    <!-- enabling annotation driven configuration /--> 
    <context:annotation-config/> 

    <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> 
     <property name="driverClassName" value="${jdbc.driverClassName}"/> 
     <property name="url" value="${jdbc.url}"/> 
     <property name="username" value="${jdbc.username}"/> 
     <property name="password" value="${jdbc.password}"/> 
    </bean> 

    <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> 
     <property name="dataSource" ref="dataSource"/> 
     <property name="configLocation"> 
      <value>classpath:hibernate.cfg.xml</value> 
     </property> 
     <property name="configurationClass"> 
      <value>org.hibernate.cfg.AnnotationConfiguration</value> 
     </property> 
    </bean> 

    <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> 
     <property name="sessionFactory" ref="sessionFactory"/> 
    </bean> 

    <tx:annotation-driven transaction-manager="transactionManager"/> 

    <!-- Scans the classpath of this application for @Components to deploy as beans --> 
    <context:component-scan base-package="com.companyname.springapp.repository" /> 
    <context:component-scan base-package="com.companyname.springapp.service" /> 

</beans> 

的hibernate.cfg.xml:

<?xml version='1.0' encoding='utf-8'?> 
<!DOCTYPE hibernate-configuration PUBLIC 
    "-//Hibernate/Hibernate Configuration DTD//EN" 
    "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> 

<hibernate-configuration> 
    <session-factory> 
     <mapping class="com.companyname.springapp.repository.UsuarioDaoImp" /> 
    </session-factory> 

</hibernate-configuration> 

我也嘗試把類Usuario.java是在數據庫中的實體,但我有同樣的問題。

問題是當我試圖獲得會話。我被告知使用OpenSessionInViewFilter,並使用SessionFactoryUtil而不是SessionFactory,但我不知道如何使用它。

有人可以幫助我嗎?謝謝

回答

2

您的sessionFactory尚未在UsuarioDaoImp中設置。嘗試使用構造函數自動裝配,而不是setSessionFactory,例如

@Repository(value = "usuarioDao") 
public class UsuarioDaoImp implements UsuarioDao { 

    private final SessionFactory sessionFactory; 

    @Autowired 
    public UsuarioDaoImp(SessionFactory sessionFactory) { 
     this.sessionFactory = sessionFactory; 
    } 

    ... 

} 
+0

好的。謝謝。它現在運行。但我有疑問。之前,我有使用EntityManager而不是SessionFactory創建的應用程序,並且我有許多內存問題,並且由於java.lang.OutOfMemoryError:Java堆空間而每天都會關閉。我問,並告訴我,問題是由於EntityManager,我應該使用SessionFactory,但我不知道我是否使用它。有了我現在所做的,你知道我是否會遇到這個問題嗎? –

+1

這是一個很難說!如果你堅持使用Hibernate,那麼使用SessionFactory是可以的。 –

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