oracle-從開始時間開始的1小時數據聚合15分鐘的時間

Question

我必須從Oracle表中獲取數據，其中我有一個名爲periodstarttime的日期字段，並且我只想獲取彙總的數據（聚合必須完成1小時數據），在幾分鐘00þ，15日，30日，45在間隔5分鐘

例如與輸入數據的一天，如果我的表我有periodstarttime作爲

periodstarttime  data 
05/04/2017 1:00:00  10 
05/04/2017 1:05:00  1 
05/04/2017 1:10:00  2 
05/04/2017 1:15:00  3 
05/04/2017 1:20:00  4 
05/04/2017 1:25:00  5 
05/04/2017 1:30:00 
and so on.... 

那麼我想我的結果看如：

periodstarttime   data with 1hr aggregation 
05/04/2017 1:00:00  data with 1hr aggregation from 1.00 to 2.00 
05/04/2017 1:15:00  data with 1hr aggregation from 1.15 to 2.15 
05/04/2017 1:30:00  data with 1hr aggregation from 1.30 to 2.30 
05/04/2017 1:45:00  data with 1hr aggregation from 1.45 to 2.45 

Answer 1

您可以使用TRUNC()和CASE截斷到最近每隔15分鐘，然後用解析函數與一窗口子句在滾動窗口得到的總和：

SELECT DISTINCT 
     periodstarttime, 
     SUM(data) OVER (ORDER BY periodstarttime 
          RANGE BETWEEN INTERVAL '0' MINUTE PRECEDING 
           AND  INTERVAL '45' MINUTE FOLLOWING 
         ) 
     AS hour_total, 
     'data with 1hr aggregation from ' 
     || TO_CHAR(periodstarttime, 'HH24:MI') 
     || ' to ' 
     || TO_CHAR(periodstarttime + INTERVAL '1' HOUR, 'HH24:MI') 
     AS range 
FROM (
    SELECT CASE 
      WHEN periodstarttime < TRUNC(periodstarttime, 'HH24') + INTERVAL '15' MINUTE 
      THEN TRUNC(periodstarttime, 'HH24') 
      WHEN periodstarttime < TRUNC(periodstarttime, 'HH24') + INTERVAL '30' MINUTE 
      THEN TRUNC(periodstarttime, 'HH24') + INTERVAL '15' MINUTE 
      WHEN periodstarttime < TRUNC(periodstarttime, 'HH24') + INTERVAL '45' MINUTE 
      THEN TRUNC(periodstarttime, 'HH24') + INTERVAL '30' MINUTE 
      ELSE TRUNC(periodstarttime, 'HH24') + INTERVAL '45' MINUTE 
     END AS periodstarttime, 
     data 
    FROM table_name 
) 
ORDER BY periodstarttime; 

Answer 2

查看分析函數的Windowing_clause。

會是這樣

select periodstarttime, 
    SUM(DATA) OVER (RANGE BETWEEN CURRENT ROW AND INTERVAL '1' HOUR FOLLOWING ORDER BY periodstarttime), 
    'data with 1hr aggregation from '||FIRST_VALUE(periodstarttime) OVER (RANGE BETWEEN CURRENT ROW AND INTERVAL '1' HOUR FOLLOWING ORDER BY periodstarttime) 
    ||' to '||LAST_VALUE(periodstarttime) OVER (RANGE BETWEEN CURRENT ROW AND INTERVAL '1' HOUR FOLLOWING ORDER BY periodstarttime) 
FROM ... 
WHERE EXTRACT(MINUTE FROM periodstarttime) IN (0,15,30,45) 

Answer 3

這裏是做這件事的一種方法：

WITH your_table AS (SELECT to_date('05/04/2017 01:00:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 10 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 01:05:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 20 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 01:10:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 30 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 01:15:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 40 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 01:20:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 50 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 01:25:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 60 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 01:30:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 70 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 01:40:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 80 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 01:50:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 90 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 02:00:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 100 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 02:10:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 110 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 02:20:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 120 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 02:30:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 130 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 02:40:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 140 DATA FROM dual UNION ALL 
        SELECT to_date('05/04/2017 03:00:00', 'dd/mm/yyyy hh24:mi:ss') periodstarttime, 150 DATA FROM dual) 
-- End of setting up data in your_table; you would not need the above since you already have a table with data in it 
-- See the below SQL for the main statement: 
SELECT DISTINCT TRUNC(periodstarttime, 'hh') + FLOOR((TRUNC(periodstarttime, 'mi') - TRUNC(periodstarttime, 'hh'))/(15/1440))*15/1440 periodstarttime, 
     sum(DATA) OVER (ORDER BY TRUNC(periodstarttime, 'hh') + FLOOR((TRUNC(periodstarttime, 'mi') - TRUNC(periodstarttime, 'hh'))/(15/1440))*15/1440 
         RANGE BETWEEN 0 PRECEDING AND 60/1440 FOLLOWING) sum_over_next_hour 
FROM your_table 
ORDER BY periodstarttime; 

PERIODSTARTTIME SUM_OVER_NEXT_HOUR 
---------------- ------------------ 
05/04/2017 01:00    660 
05/04/2017 01:15    850 
05/04/2017 01:30    770 
05/04/2017 01:45    690 
05/04/2017 02:00    750 
05/04/2017 02:15    540 
05/04/2017 02:30    290 
05/04/2017 03:00    150 

這是通過：

1. 尋找週期的開始時間，這是我們做的通過查找每個週期開始時間的分鐘數，將其除以15分鐘，找到該數字的底部，然後將其乘以新的號碼15分鐘。這將時間分成15個分鐘組。

2. 現在我們知道這些羣體，我們可以做一個累計和。因爲我們希望整個小時的價值，我們需要在當前時期和當前時期+ 1小時之間做一個範圍。注：這是包容性的，因此02:00的值將包含在01:00期間的累積金額中。如果你不想這樣做，請改變範圍，使其達到59分鐘（這很好，因爲我們的時間段現在是過去一小時的0,15,30或45分鐘）。