Java正則表達式 - 以開始和結束分割段落的正則表達式

Question

我是新來的java正則表達式。請幫助我。 考慮下面的段落，

段落：

  Name abc 
      sadghsagh 
      hsajdjah Name 
      ggggggggg 
      !!! 
      Name ggg 
      dfdfddfdf Name 
      !!! 
      Name hhhh 
      sahdgashdg Name 
      asjdhjasdh 
      sadasldkalskd 
      asdjhakjsdhja 
      !!! 

我需要拆分上述段落開頭名稱的文本塊和結尾！ 。在這裏，我不想使用！作爲分割段落的唯一分隔符。我需要在我的正則表達式中包含起始序列（Name）。

即，我的成績API應該看起來像SplitAsBlocks（ 「段落」， 「startswith名稱」， 「的endsWith !!!」）

如何實現這一點，請誰能幫我...

現在我想爲布里託給予相同的輸出...但在這裏我有「hsajdjah」之後添加名稱。這裏是分割文本beow：

Name 
ggggggggg 
!!! 

，但我需要

Name abc 
sadghsagh 
hsajdjah Name 
ggggggggg 
!!! 

這是我必須匹配名稱是在行的開始，而不是在中間。

請建議我...

巴特......看到下面的輸入情況下，爲您的代碼...

我需要拆分以下使用UR API啓動參數=>名稱和結束=>！ 但輸出變化..我只有3個塊開始與名稱和結束！ 。 我也附加了輸出。

String myInput = "Name hhhhh class0"+ "\n"+ 
        "HHHHHHHHHHHHHHHHHH"+ "\n"+ 
        "!"+ "\n"+ 
        "Name TTTTT TTTT"+ "\n"+ 
        "GGGGGG UUUUU IIII"+ "\n"+ 
        "!"+ "\n"+ 
        "Name JJJJJ WWWW"+ "\n"+ 
        "IIIIIIIIIIIIIIIIIIIII"+ "\n"+ 
        "!"+ "\n"+ 
        "RRRRRRRRRRR TTTTTTTT"+ "\n"+ 
        "HHHHHH"+ "\n"+ 
        "JJJJJ 1 Name class1"+ "\n"+ 
        "LLLLL 5 Name class5"+ "\n"+ 
        "!"+ "\n"+ 
        "OOOOOO HHHH FFFFFF"+ "\n"+ 
        "service 0 Name class12"+ "\n"+ 
        "!"+ "\n"+ 
        "JJJJJ YYYYYY 3/0"+ "\n"+ 
        "KKKKKKK"+ "\n"+ 
        "UUU UUU UUUUU"+ "\n"+ 
        "QQQQQQQ"+ "\n"+ 
         "!"; 
    String[] tokens = tokenize(myInput, "Name", "!"); 
    int n = 0; 
    for(String t : tokens) { 
     System.out.println("---------------------------\n"+(++n)+"\n"+t); 
    } 

輸出：

--------------------------- 
1 
Name hhhhh class0 
HHHHHHHHHHHHHHHHHH 
! 
--------------------------- 
2 
Name TTTTT TTTT 
GGGGGG UUUUU IIII 
! 
--------------------------- 
3 
Name JJJJJ WWWW 
IIIIIIIIIIIIIIIIIIIII 
! 
--------------------------- 
4 
Name class1 
LLLLL 5 Name class5 
! 
--------------------------- 
5 
Name class12 
! 

在這裏，我需要在該行的開始只有名稱不能在中間...... 如何添加正則表達式這個...

Answer 1

嘗試：

import java.util.*; 
import java.util.regex.*; 

public class Main { 

    public static String[] tokenize(String text, String start, String end) { 
     // old line: 
     //Pattern p = Pattern.compile("(?s)"+Pattern.quote(start)+".*?"+Pattern.quote(end)); 
     // new line: 
     Pattern p = Pattern.compile("(?sm)^"+Pattern.quote(start)+".*?"+Pattern.quote(end)+"$"); 

     Matcher m = p.matcher(text); 
     List<String> tokens = new ArrayList<String>(); 
     while(m.find()) { 
      tokens.add(m.group()); 
     } 
     return tokens.toArray(new String[]{}); 
    } 

    public static void main(String[] args) { 
     String text = "Name abc" + "\n" + 
      "sadghsagh"   + "\n" + 
      "hsajdjah Name"  + "\n" + 
      "ggggggggg"   + "\n" + 
      "!!!"    + "\n" + 
      "Name ggg"   + "\n" + 
      "dfdfddfdf Name"  + "\n" + 
      "!!!"    + "\n" + 
      "Name hhhh"   + "\n" + 
      "sahdgashdg Name" + "\n" + 
      "asjdhjasdh"   + "\n" + 
      "sadasldkalskd"  + "\n" + 
      "asdjhakjsdhja"  + "\n" + 
      "!!!"; 
     String[] tokens = tokenize(text, "Name", "!!!"); 
     int n = 0; 
     for(String t : tokens) { 
      System.out.println("---------------------------\n"+(++n)+"\n"+t); 
     } 
    } 
} 

Answer 2

String s = "Name abc sadghsagh hsajdjah !!! Name ggg dfdfddfdf !!! Name hhhh sahdgashdg asjdhjasdh sadasldkalskd asdjhakjsdhja !!!!! "; 
String startsWith = "Name"; 
String endsWith = "!!!"; 

// non-greedily get all groups starting with Name and ending with !!! 
String pattern = String.format("(%s).*?(%s)", Pattern.quote(startsWith), Pattern.quote(endsWith)); 
System.out.println(pattern); 

Matcher m = Pattern.compile(pattern, Pattern.DOTALL).matcher(s); 
while (m.find()) 
    System.out.println(m.group()); 

輸出：

(\QName\E).*?(\Q!!!\E) 
Name abc sadghsagh hsajdjah !!! 
Name ggg dfdfddfdf !!! 
Name hhhh sahdgashdg asjdhjasdh sadasldkalskd asdjhakjsdhja !!! 

Answer 3

下也應該，如果你想保持在結果都Name和!!!做。

String [] parts = string.split（「（？=（Name | !!!））」）;

編輯：這裏的修正版本：

String[] parts = string.split("(?<=!!!)\\s*(?=Name)"); 

這將各執!!!和Name，沒有別的之間的任何空白;特此保留兩部分。如果您不想分割!!!Name，則將\\s*替換爲\\s+以允許一對多匹配而不是零對多匹配。

編輯2：附上了一個輸入/輸出的例子。輸入從topicstart複製：

String string = "Name hhhhh class0" + "\n" + "HHHHHHHHHHHHHHHHHH" + "\n" + "!" + "\n" 
    + "Name TTTTT TTTT" + "\n" + "GGGGGG UUUUU IIII" + "\n" + "!" + "\n" 
    + "Name JJJJJ WWWW" + "\n" + "IIIIIIIIIIIIIIIIIIIII" + "\n" + "!" + "\n" 
    + "RRRRRRRRRRR TTTTTTTT" + "\n" + "HHHHHH" + "\n" + "JJJJJ 1 Name class1" + "\n" 
    + "LLLLL 5 Name class5" + "\n" + "!" + "\n" + "OOOOOO HHHH FFFFFF" + "\n" 
    + "service 0 Name class12" + "\n" + "!" + "\n" + "JJJJJ YYYYYY 3/0" + "\n" + "KKKKKKK" 
    + "\n" + "UUU UUU UUUUU" + "\n" + "QQQQQQQ" + "\n" + "!"; 

String[] parts = string.split("(?<=!)\\s*(?=Name)"); 
for (String part : parts) { 
    System.out.println(part); 
    System.out.println("---------------------------------"); 
} 

輸出：

Name hhhhh class0 
HHHHHHHHHHHHHHHHHH 
! 
--------------------------------- 
Name TTTTT TTTT 
GGGGGG UUUUU IIII 
! 
--------------------------------- 
Name JJJJJ WWWW 
IIIIIIIIIIIIIIIIIIIII 
! 
RRRRRRRRRRR TTTTTTTT 
HHHHHH 
JJJJJ 1 Name class1 
LLLLL 5 Name class5 
! 
OOOOOO HHHH FFFFFF 
service 0 Name class12 
! 
JJJJJ YYYYYY 3/0 
KKKKKKK 
UUU UUU UUUUU 
QQQQQQQ 
! 
--------------------------------- 

看起來不錯？