2016-12-27 46 views
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我一直在看this的例子。我基於它編寫了我的代碼,但我仍然無法弄清楚如何連接qwizard的下一個按鈕。例如,我希望每次點擊下一個按鈕時打印頁面的名稱和編號。與完成按鈕相同,單擊完成後,我希望它打印「完成!」在控制檯上,主要知道如何連接這些按鈕以在其中一個頁面中執行功能。如何將頁面的功能連接到qwizard的下一個按鈕?

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它使用一些'QtGui.QWizardPage',所以也許可以找到這個類的文檔:http:// do c.qt.io/qt-4.8/qwizardpage.html – furas

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我已閱讀文檔。仍然困惑於如何將一個函數連接到按鈕 – answerSeeker

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@TakakaiWasumi嘗試使用我的代碼 – eyllanesc

回答

1

您可以通過函數{your wizard}.button({type button}),其中按鈕類型可以得到的按鈕:

  • QtGui.QWizard.BackButton
  • QtGui.QWizard.NextButton
  • QtGui.QWizard.CommitButton
  • QtGui.QWizard.FinishButton
  • QtGui.QWizard.CancelButton
  • QtGui.QWizard.HelpButton
  • QtGui.QWizard.CustomButton1
  • QtGui.QWizard.CustomButton2
  • QtGui.QWizard.CustomButton3

代碼:

from PyQt4 import QtGui 


def createIntroPage(): 
    page = QtGui.QWizardPage() 
    page.setTitle("Introduction") 

    label = QtGui.QLabel("This wizard will help you register your copy of " 
      "Super Product Two.") 
    label.setWordWrap(True) 

    layout = QtGui.QVBoxLayout() 
    layout.addWidget(label) 
    page.setLayout(layout) 

    return page 


def createRegistrationPage(): 
    page = QtGui.QWizardPage() 
    page.setTitle("Registration") 
    page.setSubTitle("Please fill both fields.") 

    nameLabel = QtGui.QLabel("Name:") 
    nameLineEdit = QtGui.QLineEdit() 

    emailLabel = QtGui.QLabel("Email address:") 
    emailLineEdit = QtGui.QLineEdit() 

    layout = QtGui.QGridLayout() 
    layout.addWidget(nameLabel, 0, 0) 
    layout.addWidget(nameLineEdit, 0, 1) 
    layout.addWidget(emailLabel, 1, 0) 
    layout.addWidget(emailLineEdit, 1, 1) 
    page.setLayout(layout) 

    return page 


def createConclusionPage(): 
    page = QtGui.QWizardPage() 
    page.setTitle("Conclusion") 

    label = QtGui.QLabel("You are now successfully registered. Have a nice day!") 
    label.setWordWrap(True) 

    layout = QtGui.QVBoxLayout() 
    layout.addWidget(label) 
    page.setLayout(layout) 

    return page 


def backprint(): 
    print("Action: back Page: " + wizard.currentPage().title()) 

def nextprint(): 
    print("Action: next Page: " + wizard.currentPage().title()) 

def commitprint(): 
    print("Action: commit Page: " + wizard.currentPage().title()) 

def finishprint(): 
    print("Action:finish Page: " + wizard.currentPage().title()) 

def cancelprint(): 
    print("Action:cancel Page: " + wizard.currentPage().title()) 

if __name__ == '__main__': 

    import sys 

    app = QtGui.QApplication(sys.argv) 

    wizard = QtGui.QWizard() 

    wizard.addPage(createIntroPage()) 
    wizard.addPage(createRegistrationPage()) 
    wizard.addPage(createConclusionPage()) 

    wizard.button(QtGui.QWizard.BackButton).clicked.connect(backprint) 
    wizard.button(QtGui.QWizard.NextButton).clicked.connect(nextprint) 
    wizard.button(QtGui.QWizard.CommitButton).clicked.connect(commitprint) 
    wizard.button(QtGui.QWizard.FinishButton).clicked.connect(finishprint) 
    wizard.button(QtGui.QWizard.CancelButton).clicked.connect(cancelprint) 

    wizard.setWindowTitle("Trivial Wizard") 
    wizard.show() 
    print("Page :" + wizard.currentPage().title()) 

    sys.exit(wizard.exec_()) 

輸出:

Page :Introduction 
Action: next Page: Registration 
Action: next Page: Conclusion 
Action: back Page: Registration 
Action: back Page: Introduction 
Action: next Page: Registration 
Action: next Page: Conclusion 
Action:finish Page: Conclusion 
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我不斷收到:lambda:print(「Action:back Page:」+ wizard.currentPage()。title())) ^ SyntaxError :所有lambda函數的語法無效。我在Python 2.7 – answerSeeker

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@TakakaiWasumi更新我的解決方案 – eyllanesc

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再次感謝你的男人。我一直在尋找幾個小時 – answerSeeker

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