對不起,如果這是一個愚蠢的問題,我是新來的C++。爲什麼它沒有正確地將所有輸入複製到輸出?Printf打印錯誤的字符和0
#include <iostream>
#include <iomanip>
#include <limits>
#include <string>
using namespace std;
int main() {
int num1;
long num2;
long long num3;
char char1;
float num4;
double num5;
scanf("%d %ld %lld %c %f %lf", &num1, &num2, &num3, &char1, &num4, &num5);
//input: 211916801 452082285 97592151379235457 p 19856.992 -5279235.721231465
printf("%d %ld %lld %c %f %lf", num1, num2, &num3, &char1, &num4, &num5);
//expected output: 211916801 452082285 97592151379235457 p 19856.992 -5279235.721231465
//actual output: 211916801 452082285 68674564278975280 c 0.000000 0.000000
system("pause");
return 0;
}
爲什麼在第一個地方在C++代碼中使用'scanf()'和'printf()'? –
,因爲如果我使用cout它不會打印所有小數的double,但是使用printf它也可以,這就是HackerRank要我做的事情(https://www.hackerrank.com/challenges/c-tutorial-基本數據類型?h_r = next-challenge&h_v = zen) – kirill2485
檢查'std :: fixed'和'std :: setprecision()'[manipulators](http://en.cppreference.com/w/cpp/ IO/MANIP)。 –