回聲超過1個ID

Question

我想在我的數據庫中回顯超過1個ID，如何在索引頁中顯示多於1個ID？

我的功能：

function query($sql) { 
global $conn; 
$results = mysql_query($sql, $conn); 
$rows = array(); 
if(!is_bool($results)) 
    while($row = mysql_fetch_assoc($results)) 
     $rows['id'] = $row; 
    return $rows; 
} 

我的索引頁：

<?php foreach($funds as $fund) { ?> 

<td width="87%" valign="top"><ul id="funds" class="bodycopy2" style="margin:0;"> 
    <li><?php echo $fund['fund']; ?><span class="price"><div align="center" class="h1"><strong><br />R123.45</strong> <br />as at <br />1 January 2012</div></span></li> 
    <li><?php echo $fund['fund']; ?><span class="price"><div align="center" class="h1"> <strong><br />R200.45</strong> <br />as at <br />1 January 2012</div></span> </li> 
    <li><?php echo $fund['fund']; ?><span class="price"><div align="center" class="h1"> <strong><br />R150.00</strong> <br />as at <br />1 January 2012</div></span></li> 
</td> 
    </tr> 

    </table> 
    <?php } ?> 

Answer 1

你可以使用這樣一組ID：

$rows['ids'][] = $row; 

然後你可以通過IDS使用

foreach ($rows as $id) 

或直接$rows[] = $row如果你只保留ID。

Answer 2

你總是覆蓋相同的元素$rows['id'] = $row;。你應該做

$rows['id'][] = $row; 

，以顯示你應該反覆$行

foreach($rows['id'] as $id){ 
    echo $id; 
}