2011-11-20 68 views
0

我有jQuery UI - 可排序組件的問題。 問題的解釋:Jquery UI - 可排序[Portlet] - 按鈕雙擊

  • 點擊按鈕1 - >導致「警報」
  • 拖動portlet包含Button1以另一列,然後點擊按鈕1 - >導致「警報」「警報」(行動由點擊功能爲代表的每個事件兩次triggerd)從jQuery UI的網頁

簡單代碼(修改的portlet示例):

<!DOCTYPE html> 
<html lang="en"> 
<head> 
    <meta charset="utf-8"> 
    <title>jQuery UI Sortable - Portlets</title> 
    <link rel="stylesheet" href="../../themes/base/jquery.ui.all.css"> 
    <script src="../../jquery-1.6.2.js"></script> 
    <script src="../../ui/jquery.ui.core.js"></script> 
    <script src="../../ui/jquery.ui.widget.js"></script> 
    <script src="../../ui/jquery.ui.mouse.js"></script> 
    <script src="../../ui/jquery.ui.sortable.js"></script> 
    <script src="../../ui/jquery.ui.button.js"></script> 
    <link rel="stylesheet" href="../demos.css"> 
    <style> 
    .column { width: 170px; float: left; padding-bottom: 100px; } 
    .portlet { margin: 0 1em 1em 0; } 
    .portlet-header { margin: 0.3em; padding-bottom: 4px; padding-left: 0.2em; } 
    .portlet-header .ui-icon { float: right; } 
    .portlet-content { padding: 0.4em; } 
    .ui-sortable-placeholder { border: 1px dotted black; visibility: visible !important; height: 50px !important; } 
    .ui-sortable-placeholder * { visibility: hidden; } 
    </style> 
    <script> 
    $(function() { 
     $(".column").sortable({ 
      connectWith: ".column" 
     }); 

     $(".portlet").addClass("ui-widget ui-widget-content ui-helper-clearfix ui-corner-all") 
      .find(".portlet-header") 
       .addClass("ui-widget-header ui-corner-all") 
       .prepend("<span class='ui-icon ui-icon-minusthick'></span>") 
       .end() 
      .find(".portlet-content"); 

     $(".portlet-header .ui-icon").click(function() { 
      $(this).toggleClass("ui-icon-minusthick").toggleClass("ui-icon-plusthick"); 
      $(this).parents(".portlet:first").find(".portlet-content").toggle(); 
     }); 

     $(".column").disableSelection(); 
    }); 
    </script> 
</head> 
<body> 
<div class="demo"> 

<div class="column"> 

    <div class="portlet"> 
     <div class="portlet-header">Feeds</div> 
     <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> 
     <div> 
      <div id="button1"></div> 
     </div> 
     <script> 
           $("#button1").button({ 
            icons: { 
             primary: "ui-icon-locked" 
            }, 
            label: 'Button1' 
           }).click(function(){ 
            alert('Alert'); 
           }); 
     </script> 
    </div> 

    <div class="portlet"> 
     <div class="portlet-header">News</div> 
     <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> 
    </div> 

</div> 

<div class="column"> 

    <div class="portlet"> 
     <div class="portlet-header">Shopping</div> 
     <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> 
    </div> 

</div> 

<div class="column"> 

    <div class="portlet"> 
     <div class="portlet-header">Links</div> 
     <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> 
    </div> 

    <div class="portlet"> 
     <div class="portlet-header">Images</div> 
     <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> 
    </div> 

</div> 

</div><!-- End demo --> 



<div class="demo-description"> 
<p> 
    Enable portlets (styled divs) as sortables and use the <code>connectWith</code> 
    option to allow sorting between columns. 
</p> 
</div><!-- End demo-description --> 

</body> 
</html> 

回答

0

的問題是使y ou將點擊函數綁定到portlet本身的html中的button1,所以當jQuery UI克隆一個輔助對象時可能會再次執行它。解決方案很簡單,只需將您的Feeds portlet的腳本元素內的代碼移動到頁面頭部的腳本部分(在函數體中,就像由ready處理程序執行的其他代碼一樣)。