多個關鍵字搜索使用PHP MySQL的結果記錄

Question

ID CODE  STATE CITY   AREA 
1 SBIN0000952 ORISSA JAIPUR   TOWN 
2 SBIN0000953 ORISSA KURAPUT   VILLAGE 
3 SBIN0000954 DELHI DELHI   TOWN 
4 SBIN0000955 DELHI NEW DELHI  VILLAGE 
5 SBIN0000956 GOA  SOUTH GOA  VILLAGE 
6 SBIN0000957 GOA  PANAJI   TOWN 
7 SBIN0000958 KERLA CHOCHIN   TOWN 
8 SBIN0000959 KERLA TRIVANDRAM  VILLAGE 
9 SBIN0000960 ANDHRA VIZAG   TOWN 
10 SBIN0000961 ANDHRA HYDERABAD  VILLAGE 

是我的表，我想搜索多個關鍵字，例如

kerla鎮那麼它應該顯示下我現在的紀錄

7 SBIN0000958 KERLA CHOCHIN TOWN 

在PHP代碼

include('dbConnect.inc.php'); 

//collect 
if(!isset($_POST['search'])){ 
    header("Location:index.php"); 

} 
    $searchq = mysql_real_escape_string($_POST['search']); 
    $search_sql = "SELECT * FROM `bankifscin` WHERE STATE LIKE '%$searchq%' OR CITY LIKE '%$searchq%' OR CODE LIKE '%$searchq%' "; 
    $search_query = mysql_query($search_sql) or die(mysql_error()); 
    if(mysql_num_rows($search_query)!=0){ 
    $search_rs = mysql_fetch_assoc($search_query); 
    } 

打印

<?php if(mysql_num_rows($search_query)!=0){ 
    do{ ?> 

    <?php 

    $bank = $search_rs['BANK']; 
    $ifsc = $search_rs['IFSC']; 
    $branch= $search_rs['BRANCH']; 
    $micr = $search_rs['MICR_CODE']; 
    $address = $search_rs['ADDRESS']; 
    $contact = $search_rs['CONTACT']; 
    $city = $search_rs['CITY']; 
    $district = $search_rs['DISTRICT']; 
    $state = $search_rs['STATE']; 
     ?> 
     <table width="100%" border="2" bordercolor="#000" class="bdrcolor"> 


    <tbody>  
    <tr> 
    <td width="15%"><?=$bank?></td> 
     <td width="15%"><?=$branch?></td> 
     <td width="15%"><b>IFSC:</b><?=$ifsc?> <br /><b>MICR:</b><?=$micr?></td> 
     <td width="20%"><?=$address?><br /> <b>City :</b><?=$city?> <br /> <b>District :</b><?=$district?> <br /> <b>State:</b> <?=$state?></td> 
     <td width="10%"><?=$contact?></td> 
    </tr> 
    <br /> 
    </tbody> 
</table> 



    <?php }while ($search_rs = mysql_fetch_assoc($search_query)); 

}else{ 
     echo "No Results"; 

     } 


    ?> 

其只給一個關鍵詞的結果還是沒有結果

Answer 1

你應該重複你的結果集，看到的所有記錄。

$result = mysql_query($query); 
    if ($result != NULL) 
    { 
     while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) 
     { 
     foreach ($row as $key => $value) 
     { 
      // todo: use $key and $value 
     } 
     } 
     mysql_free_result($result); 
    } 

編輯：

在你不知道的情況下，呼叫mysql_fetch_array($result, MYSQL_ASSOC)真的是一回事mysql_fetch_assoc($result)。

編輯：

如果你只想看到包含所有關鍵字的記錄。然後你應該改變你的SQL查詢，你需要在你的SQL查詢中使用AND而不是OR。

"SELECT * FROM `bankifscin` WHERE STATE LIKE '%$state%' AND CITY LIKE '%$city%' AND CODE LIKE '%$code%' "; 

我猜並非所有的關鍵字都在使用。所以你可能想在運行時建立這個查詢。

$query = "SELECT * FROM `bankifscin` WHERE 1=1"; 
if ($useCity) $query .= " AND city like '%{$city_keyword}%'"; 
if ($useState) $query .= " AND state like '%{$state_keyword}%'"; 
if ($useCode) $query .= " AND code like '%{$code_keyword}%'"; 

我對你的問題沒有很好的理解。也許你只想包含關鍵字，如果他們指定？ （例如​​）

編輯：

從我從您的最後一個職位的理解。你希望輸入被分成單詞。並且每個字必須匹配至少1列。意思是所有單詞都必須用於查詢。然後，你可以試試這個：

// split the input in words 
$searchq = $_POST['search']; 
$words = explode(" ", $searchq); 
$wordCount = count($words); 

// declare which columns should be searched 
$columns = array("city", "town", "code", "area"); 
$columnCount = count($columns); 

// start from a basic query, which we will expand later 
$query = "SELECT * FROM `bankifscin` WHERE "; 

// all words should be used 
// that's why we are adding them with the 'AND' operator. 
for($i=0;$i<$wordCount;$i++) 
{ 
    $word = mysql_escape_string($words[$i]); 
    if ($i > 0) $query .= " AND "; 

    // build the condition 
    $condition = " ("; 
    for($j=0;$j<$columnCount;$j++) 
    { 
    // but each word can match any column, doesn't matter which one. 
    // that's why we are using the 'OR' operator here. 
    if ($j > 0) $condition .= " OR "; 
    $column = $columns[$j]; 
    $condition .= " {$column} like '%{$word}%' "; 
    } 
    $condition .= ") "; 
    $query .= $condition; 
} 
echo $query; 

這裏的竅門是，在運行時構建SQL，它會根據單詞的用戶已經使用的數量產生一個完全不同的查詢。

Answer 2

我假設你只得到一行。您需要用逗號替換字符串中的空格，並使用類似這樣的內容。 （$ searchq）中的城市或（$ searchq中的）城市或（$ searchq）中的代碼中的狀態「;

Answer 3

你正走錯了方向。您正在以if條件打印表格。您應該在foreach循環中執行printing部分。您只需在foreach循環之外定義<table>。

你必須使用foreach循環

<table> 
    <?php 
     $result = mysql_query($query); 
     if (!$result) 
     { 
      while ($row = mysql_fetch_array($result)) 
      { 
      foreach ($row as $key => $value) 
      { 
       <tr> /* (print the values) */ </tr> 
      } 
      } 
     } 
?> 
</table> 

注：

請停止使用mysql*，開始使用mysqli*功能

Answer 4

include('dbConnect.inc.php'); 

//collect 
    if(!isset($_POST['search'])){ 
    header("Location:index.php"); 

} 
$searchq = mysql_real_escape_string($_POST['search']); 
$search_sql = "SELECT * FROM `bankifscin` WHERE STATE='%$searchq%' and`enter code here` CITY= '%$searchq%'"; 
$search_query = mysql_query($search_sql) or die(mysql_error()); 
if(mysql_num_rows($search_query)!=0){ 
$search_rs = mysql_fetch_assoc($search_query); 
}