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我使用jQuery和AJAX從我的api獲取一堆結果。轉換從AJAX請求返回的JSON數據
這得到所有考試
$.fn.examEvents = (function() {
return $.ajax("/api/scores/exams", {
type: "GET",
data: JSON.stringify(this),
contentType: "application/json",
success: function(data, status, XHR) {
getScores(data);
}
});
});
這是我的回調函數 這得到了一堆看起來像這樣在我的控制檯對象:
[
Object { id="1", examTitle="exam I", startTime="1-1-2014T09:20:00", endTime="1-1-2014T011:20:00"}
Object { id="2", examTitle="exam II", startTime="1-2-2014T09:20:00", endTime="1-2-2014T011:20:00"}
Object { id="3", examTitle="exam III", startTime="1-3-2014T09:20:00", endTime="1-3-2014T011:20:00"}
]
function getScores(response) {
console.log(response);
//this writes out everything as a bunch
//of response objects to the console that
//contain properties(id, examTitle, startTime, endTime)
//transform them
var evt = {
title: response.examTitle,
start: response.startTime,
end: response.endTime
};
console.log(evt.title);
//this is undefined, even though the response
//objects contains a property called 'title' so I
//was expecting my console to be filled with a
//bunch of event titles.
};
因此,「工作」,意義它正在獲取數據。
但我想包裝並將該數據 轉換成另一個名爲'evt'的對象,但總是返回undefined。
所以我希望能夠做到這一點:
console.log(evt.title);
console.log(evt.start);
console.log(evt.end);
等等
所以我的問題是,我該怎麼辦呢?
謝謝!
哇,那很容易。謝謝! – SkyeBoniwell 2014-09-26 16:15:09
很高興幫助@ 999cm999 .... :) – 2014-09-26 16:15:49