如何找到在陣列中的多個元素 - JAVASCRIPT，ES6

Question

代碼：

let names= ["Style","List","Raw"]; 
let results= names.find(x=> x.includes("s"); 
console.log(results); // 

如何獲得包含「S」從數組名的名稱， 目前，我只得到一個元素結果但我需要所有事件。

Answer 1

你必須要在這種情況下使用filter，

let names= ["Style","List","Raw"]; 
let results= names.filter(x => x.includes("s")); 
console.log(results); //["List"] 

如果你希望它是不區分大小寫然後用下面的代碼，

let names= ["Style","List","Raw"]; 
let results= names.filter(x => x.toLowerCase().includes("s")); 
console.log(results); //["Style", "List"] 

爲了使案件敏感，我們有使字符串的字符全部爲小寫。

Answer 2

使用過濾器而不是查找。

let names= ["Style","List","Raw"]; 
let results= names.filter(x => x.includes("s")); 
console.log(results); 

Answer 3

但你也可以使用的forEach（）方法：

var names = ["Style","List","Raw"]; 
var results = []; 
names.forEach(x => {if (x.includes("s") || x.includes("S")) results.push(x)}); 
console.log(results); // [ 'Style', 'List' ] 

或者，如果您prefere：

names.forEach(x => {if (x.toLowerCase().includes("s")) results.push(x)});