-5
//my code is on java code on employ details using console
//my input is no.of employess
//i am taking input a employ details
//function on searching for a given employ for a given id
//代碼含義 // #String僱員[] [] =新的String [numberOfEmployees] [12];將存儲//使用詳細信息 //#字符串輸入將採用字符串格式中的員工詳細信息。ERROR Java代碼糾正它
//#字符串的選擇將採取的選擇,因爲是搜索的另一位員工
/上面的代碼是如果格式化開發簡單的Java代碼對使用管理系統/
import java.util.Scanner;
public class EmployeeManagement {
public static void main(String args[]){
Scanner read=new Scanner(System.in);
System.out.println("Enter the no.of employees");
int numberOfEmployees=read.nextInt();//GIVEN INPUT FOR NO.OF EMPLOYESS
int employeeId;
String employee[][]=new String[numberOfEmployees][12];
for(int inner=0;inner<numberOfEmployees;inner++){/*taken input on employ details*/
for(int outer=0;outer<11;outer++){
employee[inner][outer]=read.nextLine();
}
System.out.println();
}
for(int inner=0;inner<numberOfEmployees;inner++){
employee[inner][11] = (int)(Integer.parseInt(employee[inner][5])+Integer.parseInt(employee[inner][6])
+Integer.parseInt(employee[inner][7])+Integer.parseInt(employee[inner][8])
-Integer.parseInt(employee[inner][9])-Integer.parseInt(employee[inner][10]));
}
String choice;
do{
System.out.println("do you want to search enter employee id");
String input=read.nextLine();
System.out.println("do you want to continue press yes or YES");
read.nextLine();
choice =read.nextLine();
}while(choice=="yes" || choice=="YES");
for(int inner=0;inner<numberOfEmployees;inner++){
if(employee[inner][0]=="input"){
for(int outer=0;outer<12;outer++)
System.out.print(employee[inner][outer]);
}
System.out.println();
}
}
}
一)格式化代碼正確B)提出這樣的問題顯然 – Satya
這是一個憤怒的問題。請避免使用全部大寫*特別是*當您製作時**超大和大** **。 – tadman