基於Java的適配器中的HttpResponseException

Question

我正在嘗試向URL https://jazz.net/發送一個請求。我收到以下錯誤。 javascript函數 'addTwoIntegers' 的

調用失敗：未經授權」

FWLSE0101E：org.apache.http.client.HttpResponseException：由未經授權造成

這裏是我的Java代碼：

HttpGet query = new HttpGet(projectAreaURI); 
    HttpPost q= new HttpPost(projectAreaURI); 
    HttpClient httpClient=new DefaultHttpClient(); 
    HttpUtils.setupLazySSLSupport(httpClient); 
    q.addHeader("Accept","application/xml"); 

    q.addHeader("Accept-Encoding","gzip"); 
    q.addHeader("User-Agent","yes"); 
    q.addHeader("Content-Type","application/x-www-form-urlencoded"); 
    String postMessage="offlineData={'projectAreaItemId':'_iTuLUmxfEeKR3t32SVbLKQ','executables':[{'terItemId':'_TNoyQW6qEeKR3t32SVbLKQ','scriptItemId':'_DF89AW6qEeKR3t32SVbLKQ'}]}"; 
    q.setEntity(new ByteArrayEntity(
      postMessage.toString().getBytes("UTF8"))); 

    query.addHeader("Accept", "application/xml"); 


    // Access to the Service Descriptor document 
    HttpResponse response = HttpUtils.sendPostForSecureDocument(projectAreaURI, q, "ashwinimaddala", "ash_1646",httpClient); 
    if (response.getStatusLine().getStatusCode() != 200) { 
     response.getEntity().consumeContent(); 
     throw new  HttpResponseException(response.getStatusLine().getStatusCode(), response.getStatusLine().getReasonPhrase()); 
    } 
    return response.getStatusLine().getStatusCode()+""; 

sendPostForSecureDocument（）：

if (DEBUG) 
     System.out.println(">> PUT(1) " + put.getURI()); 
    HttpResponse documentResponse = httpClient.execute(put); 
    if (DEBUG) { 
     System.out.println(">> Response Headers:"); 
     HttpUtils.printResponseHeaders(documentResponse); 
    } 
    System.out.println(documentResponse.getStatusLine().getStatusCode()); 

    if (documentResponse.getStatusLine().getStatusCode() == 200) { 
     System.out.println(put.getURI()); 

     Header header = documentResponse.getFirstHeader(AUTHREQUIRED); 
     if ((header != null) && ("authrequired".equals(header.getValue()))) { 
      documentResponse.getEntity().consumeContent(); 
      HttpPost formPost = new HttpPost(serverURI 
        + "/j_security_check"); 
      List<NameValuePair> nvps = new ArrayList<NameValuePair>(); 
      nvps.add(new BasicNameValuePair("j_username", login)); 
      nvps.add(new BasicNameValuePair("j_password", password)); 
      formPost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8)); 
if (DEBUG) 
       System.out.println(">> POST " + formPost.getURI()); 
      HttpResponse formResponse = httpClient.execute(formPost); 
      if (DEBUG) 
       HttpUtils.printResponseHeaders(formResponse); 

      header = formResponse.getFirstHeader(AUTHREQUIRED); 
      if ((header != null) 
        && ("authfailed".equals(header.getValue()))) { 
       throw new InvalidCredentialsException(
         "Authentication failed"); 
      } else { 
       formResponse.getEntity().consumeContent(); 
       if (DEBUG) 
        System.out.println(">> PUT(2) " + put.getURI()); 
       try { 
        HttpPut put2 = (HttpPut) put.clone(); 
        return httpClient.execute(put2); 
       } catch (CloneNotSupportedException e) { 
        e.printStackTrace(); 
       } 
      } 
     } 
    } 
    return documentResponse; 

Answer 1

重新訪問了這個問題，在我看來，這可能是同樣的問題這裏報告：org.apache.http.conn.HttpHostConnectException: Connection to https://jazz.net refused

基本上，jazz.net需要使用端口443所以在Java代碼中，就像在一個工作燈適配器，請確保您使用端口443 ...