PHP從多維數組中找到值，然後將它們放在一個數組中

我有一個數組，其中包含來自數據庫的一組信息，但其中一些數據是重複的，只有數組最深處的值爲1 。例如：PHP從多維數組中找到值，然後將它們放在一個數組中

[0] => Array(['id'] => 1 , ['name'] => "First Array" , ['more'] => "stuff") 
[1] => Array(['id'] => 2 , ['name'] => "Second Array" , ['more'] => "stuff1") 
[2] => Array(['id'] => 2 , ['name'] => "Second Array" , ['more'] => "stuff2") 
[3] => Array(['id'] => 3 , ['name'] => "Third Array" , ['more'] => "stuff3") 
[4] => Array(['id'] => 3 , ['name'] => "Third Array" , ['more'] => "stuff4")

我想要做的就是用相同的[「身份證」]字段中的任何陣列到陣列的陣列，而不是[「更多」]。例如：

[0] => Array(['id'] => 1 , ['name'] => "First Array" , ['more'] => "stuff") 
[1] => Array(['id'] => 2 , ['name'] => "Second Array" , ['more'] => Array([0] => "stuff1" , [1] => "stuff2")) 
[2] => Array(['id'] => 2 , ['name'] => "Third Array" , ['more'] => Array([0] => "stuff3" , [1] => "stuff4"))

我試圖做這幾種方法，但我可以得到最接近的是這將會把所有的[「更多」]值到1門陣列這樣的功能：

[0] => Array(['id'] => 1 , ['name'] => "First Array" , ['more'] => "stuff") 
[1] => Array(['id'] => 2 , ['name'] => "Second Array" , ['more'] => Array([0] => "stuff1" , [1] => "stuff2" , [2] => "stuff3" , [3] => "stuff4"))

這就是從這樣的功能：

<?php 
private function compress_duplicates($a = array()) { 
    $diff_key = array_diff_key($a , array_unique($a)); 
    $first_key = array_shift(array_keys($diffkey)); 
    $array["id"] = $diff_key[$first_key]["id"]; 
    $array["name"] = $diff_key[$first_key]["name"]; 
    foreach($diff_key as $term) { 
     $array["more"][] = $term["more"]; 
    } 
    return $array; 
} 
?>

基本上我問的：我怎樣才能找到一個多維數組複製，然後將每個這些重複的到自己的陣列？

來源

2011-09-04 Ben

$result = array(); 
foreach ($array as $elem) { 
    if (isset($result[$elem['id']])) { 
     $result[$elem['id']]['more'] = array_merge((array)$result[$elem['id']]['more'], 
                array($elem['more'])); 
    } else { 
     $result[$elem['id']] = $elem; 
    } 
}

任選接着$result = array_values($result)，如果你想重置$result陣的鑰匙。

來源

2011-09-04 22:50:22 deceze

PHP從多維數組中找到值，然後將它們放在一個數組中

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