從一個foreach語句中檢索變量並在另一個foreach語句中顯示

Question

我想在另一個數組的foreach語句中使用一個數組中的變量。

我有一個網格視圖，顯示用戶的個人資料照片，他們的顯示名稱，當前位置和可用性，以及使用他們的用戶名來完成應用於該框的鏈接。

用戶表保存;用戶名（和用戶ID）應該在將來需要。

配置文件表保存;顯示名稱。

profilephotos表保存;個人資料照片。

位置表保存;當前位置。

所有通過與用戶表匹配的user_id和username列都鏈接到表中。

我對用戶框的代碼是;

<?php foreach($rows as $row): ?> 
<div class="box"> 
    <div class="boxInner"> 
     <a href="profile.php?username=<?php echo htmlentities($row['username'], ENT_QUOTES, 'UTF-8'); ?>&uid=<?php echo htmlentities($row['id'], ENT_QUOTES, 'UTF-8'); ?>"> 


     <img src="uploads/profile-photos/<?php echo htmlentities($pphoto['profilephoto_file'], ENT_QUOTES, 'UTF-8'); ?>" /> 


     <div class="titleBox" style="text-align:left; line-height:20px;"> 
     <span style="font-size:18px; font-weight:bold;"><i class="fa fa-user"></i> <?php echo htmlentities($row['profile_displayname'], ENT_QUOTES, 'UTF-8'); ?>, 
     <?php echo htmlentities($row['profile_displayage'], ENT_QUOTES, 'UTF-8'); ?></span> 
     <br /> 
     <span style="font-size:14px;"><i class="fa fa-map-marker"></i> City Name &nbsp;|&nbsp; <i class="fa fa-clock-o"></i> Now</span> 
     </div></a> 
    </div> 
    </div> 
<?php endforeach; ?> 

我的SQL查詢和數組代碼是;

$query = " 
     SELECT 
      users.id, 
      users.username, 
      users.email, 
      profiles.profile_displayname, 
      profiles.profile_displayage, 
      profiles.profile_photo 
     FROM users, profiles 
     WHERE users.id = profiles.user_id; 
    "; 

    try 
    { 
     // These two statements run the query against your database table. 
     $stmt = $db->prepare($query); 
     $stmt->execute(); 
    } 
    catch(PDOException $ex) 
    { 
     // Note: On a production website, you should not output $ex->getMessage(). 
     // It may provide an attacker with helpful information about your code. 
     die("Failed to run query: " . $ex->getMessage()); 
    } 

    // Finally, we can retrieve all of the found rows into an array using fetchAll 
    $rows = $stmt->fetchAll(); 

    $query = " 
     SELECT 
      users.id, 
      users.username, 
      profilephotos.user_id, 
      profilephotos.profilephoto_file 
     FROM users, profilephotos 
     WHERE users.id = profilephotos.user_id; 
    "; 

    try 
    { 
     // These two statements run the query against your database table. 
     $stmt = $db->prepare($query); 
     $stmt->execute(); 
    } 
    catch(PDOException $ex) 
    { 
     // Note: On a production website, you should not output $ex->getMessage(). 
     // It may provide an attacker with helpful information about your code. 
     die("Failed to run query: " . $ex->getMessage()); 
    } 

    // Finally, we can retrieve all of the found rows into an array using fetchAll 
    $profilephotos = $stmt->fetchAll(PDO::FETCH_ASSOC); 

無論我嘗試什麼 - 我只是不能讓foreach拉入正確的圖像。我設法拉入一張圖片，但foreach語句對每個用戶都應用相同的圖片，而不管我指示查詢$profilephotos的查詢的ID。

我在做什麼錯？我甚至會以正確的方式去做這件事嗎？

任何幫助將不勝感激 - 請注意，雖然我是PHP新手。

Answer 1

您需要一個查詢而不是兩個。 查詢可能是這樣的：

SELECT 
      users.id AS id, 
      users.username AS username, 
      users.email as email, 
      profilephotos.profilephoto_file AS file_photo, 
      profiles.profile_displayname AS file_displayname, 
      profiles.profile_displayage AS displaypage, 
      profiles.profile_photo AS photo 
     FROM users 
     JOIN profilephotos ON users.id = profilephotos.user_id 
     JOIN profiles ON users.id = profiles.user_id; 

你需要兩個用連接 - 這是更好的做法。 注意關鍵字'AS' - 它有助於消除不同表格中相同列名的歧義。

Answer 2

如果你想看到查詢變種之一（與最新的配置文件圖像），就是這樣：

SELECT 
      users.id AS id, 
      users.username AS username, 
      users.email as email, 
      profilephotos.profilephoto_file AS file_photo, 
      profiles.profile_displayname AS file_displayname, 
      profiles.profile_displayage AS displaypage, 
      profiles.profile_photo AS photo 
     FROM users 
     LEFT JOIN profiles ON users.id = profiles.user_id 
     LEFT JOIN profilephotos ON users.id = profilephotos.user_id 
     WHERE profilephotos.id in (select max(id) from profilephotos group by user_id) 
     ORDER BY id 

但我認爲它過於複雜，可能是錯誤的，在所有的，因爲我不不瞭解你的表格模式。