Codeigniter：日期驗證

Question

有誰知道如何驗證日期。例如，cannot have 30 Feb和no 31 in certain month，所以當用戶輸入有效時，它將被拒絕。我正在考慮回撥功能，但不知道如何完成。

Answer 1

使用PHP checkdate功能

使用this guide在笨創建回調函數創建一個回調函數。

Answer 2

您可以使用簡單的正則表達式來驗證日期dd-mm-yyyy格式

$this->form_validation->set_rules('dob', 'Date in dd-mm-yyyy', 
     'regex_match[(0[1-9]|1[0-9]|2[0-9]|3(0|1))-(0[1-9]|1[0-2])-\d{4}]'); 

使用callback確認這將確保月月這是28天使用

//Add a rule for validation 
$this->form_validation->set_rules('dob', 'Date of Birth', 'callback_valid_date'); 

//Define a callback and pass the format of date 
public function valid_date($date, $format = 'Y-m-d') 
{ 
    $d = DateTime::createFromFormat($format, $date); 
    //Check for valid date in given format 
    if($d && $d->format($format) == $date) { 
     return true; 
    } else { 
    $this->form_validation->set_message('valid_date', 
       'The %s date is not valid it should match this ('.$format.') format'); 
     return false; 
    } 
} 

Answer 3

嘗試這樣做的代碼也考慮閏年

function valid_date($date) 
{  
    $pattern = '/^(?:(?:31(\/|-|\.)(?:0?[13578]|1[02]))\1|(?:(?:29|30)(\/|-|\.)(?:0?[1,3-9]|1[0-2])\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:29(\/|-|\.)0?2\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:0?[1-9]|1\d|2[0-8])(\/|-|\.)(?:(?:0?[1-9])|(?:1[0-2]))\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$/'; 

    if(preg_match($pattern, $date)) 
    { 
     return true; 
    } 
    else 
    { 
     $this->form_validation->set_message('valid_date', 'The %s is not valid it should match this dd/md/yyyy format'); 
     return false; 
    } 
} 
//and just use this to set rules 
$this->form_validation->set_rules('Your date field from html', 'date', 'required|callback_valid_date');