這裏,似乎像它應該爲你工作的方式。
一些假設:
- 我想重複的是不包括ID的實際行重複,根據您提供1秒條款。如果不是這種情況...刪除分區的部分
row_number()
窗口函數,它將改變行爲
- 這將刪除遞歸重複項。也就是說,如果3,4,甚至15排在彼此的一秒鐘內,它保持1
- 這應該不論工作,如果第一行或最後一行是重複
下面的代碼。取消註釋了兩行在表中看到的變化
declare @table table(id int, var1 int, var2 int, var3 int, date datetime2)
insert into @table
values
--(0,1,2,3,'2001-01-01 00:01:01.456'),
(1,1,2,3,'2001-01-01 01:01:01.456'), --dupe of 1/2/3
(2,1,2,3,'2001-01-01 01:01:02.214'), --dupe of 1/2/3
(3,1,2,3,'2001-01-01 01:01:02.234'), --dupe of 1/2/3
(4,1,2,3,'2001-01-01 01:01:02.244'), --dupe of 1/2/3
(5,1,2,3,'2001-01-01 01:01:04.789'), --dupe of 4/5
(6,1,2,3,'2001-01-01 01:01:04.989'), --dupe of 4/5
--(7,1,2,3,'2001-01-01 01:01:06.789'), --dupe of 6/7
(8,1,2,3,'2001-01-01 01:01:06.799') --dupe of 6/7
--apply the sequence
;with cte as(
select
*,
ROW_NUMBER() over (partition by var1, var2, var3 order by date) as RN --just in case... change this to just order by id, date if need be and remove the partition
from
@table),
--get first/most of the batch to remove
cte2 as(
select
c1.*
,c2.RN as RowsToRemove
from cte c1
left join
cte c2 on c1.RN < c2.rn and
datediff(second,c1.date,c2.date) < 1),
--remove the rows identified in the above cte
cte3 as(
select distinct
ID,
var1,
var2,
var3,
date,
RN
from cte2
where
RN not in (select distinct isnull(RowsToRemove,0) from cte2)),
--add another sequence. This is necessary for first/last row check for duplicate
cte4 as(
select
f.*,
row_number() over (partition by var1, var2, var3 order by date) RN2
from
cte3 f)
--return the results
select
f.ID,
f.var1,
f.var2,
f.var3,
f.date
from
cte4 f
left join
cte4 d on d.RN = f.RN - 1
where isnull(datediff(second,d.date,f.date),500) > 1
退貨
+----+------+------+------+-----------------------------+
| ID | var1 | var2 | var3 | date |
+----+------+------+------+-----------------------------+
| 1 | 1 | 2 | 3 | 2001-01-01 01:01:01.4560000 |
| 5 | 1 | 2 | 3 | 2001-01-01 01:01:04.7890000 |
| 8 | 1 | 2 | 3 | 2001-01-01 01:01:06.7990000 |
+----+------+------+------+-----------------------------+
什麼,如果有對方的第二個中的三個記錄......只保留1?並且ID只是一個PK,這意味着var1,var2和var3應該被認爲是重複的?即如果它們不相同,那麼它不是重複的? – scsimon
@scsimon是的。所有記錄var1,2和3是相同的,日期在1秒內,只能保留1條記錄。如果在該範圍內有2個或200個,則無關緊要。 Id是PK。 – RossD
感謝@RossD的澄清。我剛剛編輯了我的答案,我*瘦*它應該在所有情況下工作。讓我知道如果它不。爲了清晰起見,我將它放在多個cte中。 – scsimon