好,我做到了....
只是讓大家看到... this.dService是DocsService,已經被驗證。
// This method returns the Resource ID to be used to make the copy
public String loadDocsSpreadsheetEntryId(String sourceName) {
String resourceId = null;
try {
Logger.info("Loading feed URL");
URL url = new URL("https://docs.google.com/feeds/default/private/full");
DocumentQuery query = new DocumentQuery(url);
query.setTitleQuery(sourceName);
query.setTitleExact(true);
Logger.info("Loaded feed URL");
DocumentListFeed dfeed = this.dService.getFeed(query, DocumentListFeed.class);
Logger.info("got feed");
for (DocumentListEntry entry : dfeed.getEntries()) {
Logger.info(entry.getTitle().getPlainText());
if(entry.getTitle().getPlainText().equalsIgnoreCase(sourceName))
{
Logger.info("found doc");
resourceId = entry.getResourceId();
}
}
} catch(Exception e) {
logException(e, "Loading Source Spreadsheet to copy");
}
return resourceId;
}
public void createSpreadsheetFrom(String destination, String source) {
try {
URL entryUrl = new URL("http://docs.google.com/feeds/default/private/full");
Map<String, String> parameters = new HashMap<String, String>();
String resourceID = loadDocsSpreadsheetEntryId(source);
Logger.info("Resource id %s", resourceID);
DocumentListEntry newEntry = new DocumentListEntry();
newEntry.setId(resourceID);
newEntry.setTitle(new PlainTextConstruct(destination));
this.dService.insert(entryUrl, newEntry);
} catch(Exception e) {
logException(e, "Copying Spreadsheet");
}
}
感謝馬克發佈您的解決方案,這正是我一直在尋找的東西,我處於需要複製電子表格的相同情況。很有幫助! – Brummo 2011-01-01 23:44:06