警告:mysqli_num_rows()期望參數1爲mysqli_result,布爾值給出 iam無法登錄,並且在給定錯誤之上會被通知,請提出更正。謝謝。 警告:mysqli_num_rows()期望參數1是mysqli_result,布爾給定 iam無法登錄,並且在給定的錯誤之上被通知。建議更正。謝謝。警告:mysqli_num_rows()期望參數1是mysqli_result,布爾給定
<html>
<head>
<title>Login page</title>
</head>
<style type='text/css'>
body{
background:url('Login.jpg');
}
</style>
<body>
<form method ='post' action='login.php'>
<table width='400' border='5' align='center'>
<tr>
<td colspan='5' align='center'><h1><font color="MediumBlue">Login form</h1></font>
</td>
</tr>
<tr>
<td><font color='DarkOrange'>email</font>
</td>
<td><input type='text' name='email'/></td>
</tr>
<tr>
<td><font color='DarkOrange'>Password</font></td>
<td><input type='password' name='pass'/></td>
</tr>
<tr>
<td colspan='5' align='center'><input type='submit' name='login' value='login'/> </td>
</tr>
</form>
<font color="LightSalmon"><h2><p style="position: fixed; bottom: 50%; width:100%; text-align: center"> Not registered yet?<a href='registration.php'>Sign up here</a>
</p><h2></font>
</body>
</html>
<?php
$connection=mysqli_connect("localhost","root","","user_db");
if(isset($_POST['login'])){
$user_Email=$_POST['email'];
$user_password=$_POST['pass'];
if($user_Email==''){
echo "<script>alert('please enter your email')</script>";
exit();
}
if($user_password==''){
echo "<script>alert('please enter your password')</script>";
exit();
}
$check_user="select * from users where user_email =='$user_Email' AND user_password =='$user_password'";
$result= mysqli_query($connection,$check_user);
$count=mysqli_num_rows($result);
if ($count==1)
{
echo"<script>window.open('welcome.php','_blank')</script>";
}
else{
echo"<script>alert('username or password is incorrect')</script>";
}
}
?>
在查詢中將==更改爲= – 2014-08-27 22:33:24
已經諮詢了我在下面給出的答案嗎? – 2014-08-30 14:31:08