所以我想在我的數據庫中的圖像的鏈接:動態PHP數組結構
$findMyImages = "SELECT link FROM images WHERE model_id ='{$me['id']}'";
$imageResult = mysql_query($findMyImages) or die (mysql_error());
$result_array = array();
while($row = mysql_fetch_array($imageResult))
{
$result_array[] = $row;
}
print_r($result_array);
的print_r();
返回此:
Array (
[0] => Array (
[0] => http://scoutsamerica.com/uploads/529746_10200706796941357_1747291081_n.jpg
[link] => http://scoutsamerica.com/uploads/529746_10200706796941357_1747291081_n.jpg
)
[1] => Array (
[0] => http://scoutsamerica.com/uploads/64311_10200924054292655_1770658989_n.jpg
[link] => http://scoutsamerica.com/uploads/64311_10200924054292655_1770658989_n.jpg
)
)
我正在尋找類似的東西:
Array (
[0] => http://scoutsamerica.com/uploads/529746_10200706796941357_1747291081_n.jpg
[1] => http://scoutsamerica.com/uploads/64311_102n_image.jpg
[2] => http://scoutsamerica.com/uploads/face.jpg
[3] => http://scoutsamerica.com/uploads/another_image.jpg
)
我該怎麼做?
我知道我不是在尋找mysql_fetch_assoc();我想要鑰匙(它們被稱爲鑰匙,不是?)是一個整數索引。 – 2013-05-01 23:52:51
* [PDO](http://php.net/manual/en/book.pdo.php)rant here * – moonwave99 2013-05-01 23:54:27
是的,我同意@ moonwave99,檢查PDO,它更安全並且是最新的。針對mysql_的開發已被佔用,因此其過時且容易受到攻擊。 – Xethron 2013-05-02 00:05:02