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我已經提供了一個模擬該場景的最小代碼。下面是代碼：結構的二進制序列化未初始化陣列
using System;
using System.IO;
using System.Runtime.Serialization.Formatters.Binary;
using System.Collections.Generic;
namespace Serialization
{
class Program
{
static void Main(string[] args)
{
string[] annotates = { "1", "2"};
Guides[] g1 = new Guides[2];
g1[0].comments = (string[])annotates.Clone();
g1[1].comments = (string[])annotates.Clone();
Guides[] g2 = new Guides[2];
g2[0].comments = (string[])annotates.Clone();
g2[1].comments = (string[])annotates.Clone();//to be commented later
arrayStruct arrStr1 = new arrayStruct();
arrStr1.guides_array = g1;
arrayStruct arrStr2 = new arrayStruct();
arrStr2.guides_array = g2;
using (MoveSaver objSaver = new MoveSaver(@"C:\1.bin"))
{
MoveAndTime mv1 = new MoveAndTime();
MoveAndTime mv2 = new MoveAndTime();
mv1.MoveStruc = "1";
mv1.timeHLd = DateTime.Now;
mv1.arr = arrStr1;
objSaver.SaveToFile(mv1);
mv2.MoveStruc = "2";
mv2.timeHLd = DateTime.Now;
mv2.arr = arrStr2;
objSaver.SaveToFile(mv2);
}
using (MoveSaver svrObj = new MoveSaver())
{
List<MoveAndTime> MVTobjs = svrObj.DeSerializeObject(@"C:\1.bin");
foreach (MoveAndTime item in MVTobjs)
{
Console.WriteLine(item.arr.guides_array[0].comments[0]);
}
}
}
}
public class MoveSaver : IDisposable
{
public void Dispose()
{
if (fs != null)
{
fs.Close();
}
}
FileStream fs;
StreamWriter sw;
public string filename { get; set; }
public MoveSaver(string FileName)
{
this.filename = FileName;
fs = new FileStream(filename, FileMode.OpenOrCreate, FileAccess.ReadWrite);
}
public MoveSaver()
{
}
~MoveSaver()
{
if (fs != null)
{
fs.Close();
}
}
public List<MoveAndTime> DeSerializeObject(string filename)
{
List<MoveAndTime> retList = new List<MoveAndTime>();
MoveAndTime objectToSerialize;
Stream stream = File.Open(filename, FileMode.Open);
BinaryFormatter bFormatter = new BinaryFormatter();
while (stream.Position != stream.Length)
{
objectToSerialize = (MoveAndTime)bFormatter.Deserialize(stream);
retList.Add(objectToSerialize);
}
stream.Close();
return retList;
}
public bool SaveToFile(MoveAndTime moveTime)
{
try
{
BinaryFormatter bformatter = new BinaryFormatter();
bformatter.Serialize(fs, moveTime);
return true;
}
catch (Exception)
{
return false;
}
}
}
[Serializable]
public struct MoveAndTime
{
public string MoveStruc;
public DateTime timeHLd;
public arrayStruct arr;
}
[Serializable]
public struct arrayStruct
{
public Guides[] guides_array;
}
[Serializable]
public struct Guides
{
public string[] comments;
public string name;
}
}
在這種代碼的一個結構包含多個結構，其中一個包含的陣列。嘗試一下代碼，它編譯得很好，但是在真實場景中，整個數組並沒有被填充，所以會有其他數組元素未指定。要看到這種效果（在行動！）註釋行g2[1].comments = (string[])annotates.Clone();並立即嘗試代碼。您將在反序列化時遇到錯誤。我怎樣才能避免它？我應該將包含該數組的結構定義爲一個類並將它們全部新建（希望我正在尋找基於結構的類的解決方案）？
編輯： 我更改了結構類，並通過新的每個實例工作正常。這裏是代碼：
using System;
using System.IO;
using System.Runtime.Serialization.Formatters.Binary;
using System.Collections.Generic;
namespace Serialization
{
class Program
{
static void Main(string[] args)
{
string[] annotates = { "1", "2"};
GuidesClass[] g1 = new GuidesClass[2];
g1[0] = new GuidesClass();
g1[0].comments = (string[])annotates.Clone();
g1[1] = new GuidesClass();
g1[1].comments = (string[])annotates.Clone();
GuidesClass[] g2 = new GuidesClass[2];
g2[0] = new GuidesClass();
g2[0].comments = (string[])annotates.Clone();
g2[1] = new GuidesClass();
//g2[1].comments = (string[])annotates.Clone();
array_cls arrStr1 = new array_cls();
arrStr1.guides_array = g1;
array_cls arrStr2 = new array_cls();
arrStr2.guides_array = g2;
using (MoveSaver objSaver = new MoveSaver(@"C:\1.bin"))
{
M_T mv1 = new M_T();
M_T mv2 = new M_T();
mv1.MoveStruc = "1";
mv1.timeHLd = DateTime.Now;
mv1.arr = arrStr1;
objSaver.SaveToFile(mv1);
mv2.MoveStruc = "2";
mv2.timeHLd = DateTime.Now;
mv2.arr = arrStr2;
objSaver.SaveToFile(mv2);
}
using (MoveSaver svrObj = new MoveSaver())
{
List<M_T> MVTobjs = svrObj.DeSerializeObject(@"C:\1.bin");
foreach (M_T item in MVTobjs)
{
Console.WriteLine(item.arr.guides_array[0].comments[0]);
}
}
}
}
public class MoveSaver : IDisposable
{
public void Dispose()
{
if (fs != null)
{
fs.Close();
}
}
FileStream fs;
StreamWriter sw;
public string filename { get; set; }
public MoveSaver(string FileName)
{
this.filename = FileName;
fs = new FileStream(filename, FileMode.OpenOrCreate, FileAccess.ReadWrite);
}
public MoveSaver()
{
}
~MoveSaver()
{
if (fs != null)
{
fs.Close();
}
}
public List<M_T> DeSerializeObject(string filename)
{
List<M_T> retList = new List<M_T>();
M_T objectToSerialize;
Stream stream = File.Open(filename, FileMode.Open);
BinaryFormatter bFormatter = new BinaryFormatter();
while (stream.Position != stream.Length)
{
objectToSerialize = (M_T)bFormatter.Deserialize(stream);
retList.Add(objectToSerialize);
}
stream.Close();
return retList;
}
public bool SaveToFile(M_T moveTime)
{
try
{
BinaryFormatter bformatter = new BinaryFormatter();
bformatter.Serialize(fs, moveTime);
return true;
}
catch (Exception)
{
return false;
}
}
}
[Serializable]
public class M_T
{
public string MoveStruc;
public DateTime timeHLd;
public array_cls arr;
}
[Serializable]
public class array_cls
{
public GuidesClass[] guides_array = new GuidesClass[10];
}
[Serializable]
public class GuidesClass
{
public string[] comments;
public string name;
}
}
什麼錯誤？ – Oded 2011-03-05 08:58:32
出於好奇，**爲什麼**是結構？他們看起來不像典型的結構（特別是因爲他們是可變的），並且沒有充分的理由，他們應該默認爲類。 – 2011-03-05 09:14:24
@Oded：「輸入流不是有效的二進制格式」，在實際的代碼中，錯誤與二進制頭相關。嘗試用註釋行編譯代碼，您將看到錯誤。 – 2011-03-05 09:30:45