2017-04-15 142 views
1

我試圖使用typeahead。如何獲取json數據並轉換爲像狀態的jquery數組?我已閱讀文檔,但沒有運氣與此。 (我用,1.9.1 jquery,Laravel 5.1)獲取json數據並使用Laravel轉換爲數組

下面是工作,但狀態數組是靜態的。我想從MySql數據庫異步獲取數據。這個怎麼做?

的jQuery:

var substringMatcher = function(strs) { 
    return function findMatches(q, cb) { 
    var matches, substringRegex; 

    // an array that will be populated with substring matches 
    matches = []; 

    // regex used to determine if a string contains the substring `q` 
    substrRegex = new RegExp(q, 'i'); 

    // iterate through the pool of strings and for any string that 
    // contains the substring `q`, add it to the `matches` array 
    $.each(strs, function(i, str) { 
     if (substrRegex.test(str)) { 
     matches.push(str); 
     } 
    }); 

    cb(matches); 
    }; 
}; 

var states = ['Alabama', 'Alaska', 'Arizona', 'Arkansas', 'California', 
    'Colorado', 'Connecticut', 'Delaware', 'Florida', 'Georgia', 'Hawaii', 
    'Idaho', 'Illinois', 'Indiana', 'Iowa', 'Kansas', 'Kentucky', 'Louisiana', 
    'Maine', 'Maryland', 'Massachusetts', 'Michigan', 'Minnesota', 
    'Mississippi', 'Missouri', 'Montana', 'Nebraska', 'Nevada', 'New Hampshire', 
    'New Jersey', 'New Mexico', 'New York', 'North Carolina', 'North Dakota', 
    'Ohio', 'Oklahoma', 'Oregon', 'Pennsylvania', 'Rhode Island', 
    'South Carolina', 'South Dakota', 'Tennessee', 'Texas', 'Utah', 'Vermont', 
    'Virginia', 'Washington', 'West Virginia', 'Wisconsin', 'Wyoming' 
]; 

$('#the-basics .typeahead').typeahead({ 
    hint: true, 
    highlight: true, 
    minLength: 1 
}, 
{ 
    name: 'states', 
    source: substringMatcher(states) 
}); 

我的路線是:

Route::get('search', array('as' => 'searchlive', 'uses' => '[email protected]')); 

我的控制器:

public function searchlive(Request $request) 
    { 
     $search = $request->thesearch; 
     $games = Game::where('id', 'LIKE', '%' . $search . '%') 
      ->orwhere('name', 'LIKE', '%' . $search . '%') 
      ->orwhere('title', 'LIKE', '%' . $search . '%')->take(5)->get(); 

     return Response()->json($games); 
    } 
+0

? – GabMic

回答

1

爲什麼你需要,如果你只需要數組到您的預輸入獲取JSON數據jQuery代碼。只是使一個數組控制器,並把它傳遞給你的預輸入代碼,例如:

public function searchlive(Request $request) 
{ 
    $search = $request->thesearch; 
    $games = Game::where('id', 'LIKE', '%' . $search . '%') 
     ->orwhere('name', 'LIKE', '%' . $search . '%') 
     ->orwhere('title', 'LIKE', '%' . $search . '%')->take(5)->get(); 

     $gamesarray = $games->toArray(); 
     return view('yourbladefilename', compact(['gamesarray'])) 
} 

而在刀片文件替換:

var states = ['Alabama', 'Alaska', 'Arizona', 'Arkansas', 'California', 
    'Colorado', 'Connecticut', 'Delaware', 'Florida', 'Georgia', 'Hawaii', 
    'Idaho', 'Illinois', 'Indiana', 'Iowa', 'Kansas', 'Kentucky', 'Louisiana', 
    'Maine', 'Maryland', 'Massachusetts', 'Michigan', 'Minnesota', 
    'Mississippi', 'Missouri', 'Montana', 'Nebraska', 'Nevada', 'New Hampshire', 
    'New Jersey', 'New Mexico', 'New York', 'North Carolina', 'North Dakota', 
    'Ohio', 'Oklahoma', 'Oregon', 'Pennsylvania', 'Rhode Island', 
    'South Carolina', 'South Dakota', 'Tennessee', 'Texas', 'Utah', 'Vermont', 
    'Virginia', 'Washington', 'West Virginia', 'Wisconsin', 'Wyoming' 
]; 

var states = {!! $gamesarray !!} 

希望它有助於..如果有任何問題請發表評論。如果你有'dd($遊戲)',你會得到什麼?

+0

首先,searchlive函數,是我的第二個類,gamearray變量沒有被識別爲值。 sql的第二個請求需要是異步的,以便只提取請求的數據,而不是從開始的所有內容。不錯,儘管。我的第一類返回視圖是: 公共功能索引(Request $ request) { $ games = Game :: orderBy('id','asc') - > get(); \t return view('webapp.scores',compact('games')); } –

+1

您也可以根據您的要求自定義以上代碼。 –

+0

我需要一個ajax函數將這些值返回給javascript數組。上面的代碼不起作用。 –