SQLITE - 合併與伯爵的和sum的兩個表爲一個結果

我有這兩個查詢：SQLITE - 合併與伯爵的和sum的兩個表爲一個結果

SELECT 
    b.ref, 
    ts.id_baits, 
    SUM(strftime('%s',ts.endtime) -strftime('%s',ts.initime)) AS t,COUNT(*) AS n 
FROM TimeSegments AS ts 
INNER JOIN Baits AS b ON b.id = ts.Id_Baits 
GROUP BY ts.id_baits 
ORDER BY b.ref 


SELECT b.ref, 
    COUNT(CASE WHEN e.Status=1 THEN 1 END) AS Undefined, 
    COUNT(CASE WHEN e.Status=1 THEN 1 END) AS GetClose, 
    COUNT(CASE WHEN e.Status=2 THEN 1 END) AS Threat, 
    COUNT(CASE WHEN e.Status=3 THEN 1 END) AS Attack, 
    COUNT(CASE WHEN e.Status=4 THEN 1 END) AS Hooked, 
    COUNT(CASE WHEN e.Status=5 THEN 1 END) AS Captured, 
    COUNT(CASE WHEN e.Status=6 THEN 1 END) AS Tagged, 
    COUNT (*) AS TOTAL 
FROM CastingsEvents AS e 
LEFT JOIN Trajectories AS tr ON tr.id = e.id_trajectories 
LEFT JOIN TimeSegments AS ts ON ts.id = tr.id_timesegments 
LEFT JOIN Baits AS b ON b.id = ts.Id_Baits 
GROUP BY ts.id_baits 
ORDER BY b.ref

可以看出，這兩個表由id_baits分組。

我想將結果合併到一張表中，有人知道它是如何做到的？

來源

2017-10-10 sgm

我想，這可能有助於[UNION子句（https://www.tutorialspoint.com/sqlite/sqlite_unions_clause.htm） – Jerrol

「合併」是什麼意思？請提供一些示例數據和您想要的輸出。（請參閱[如何格式化堆棧溢出中的SQL表後？]（https://meta.stackexchange.com/q/96125）如何添加一些內容。） –

Hello Jerrol，UNION子句需要兩個表都有相同的列（正確的？），情況並非如此。 – sgm

的提議（JOIN two SELECT statement results），一個LEFT JOIN解決的問題：

SELECT * FROM (
    SELECT 
     b.ref AS bait, 
     ts.id_baits, 
     SUM(strftime('%s',ts.endtime) -strftime('%s',ts.initime)) AS t, 
     COUNT(*) AS n 
    FROM TimeSegments as ts 
    INNER JOIN Baits as b ON b.id = ts.id_baits 
    GROUP BY ts.id_baits 
) BaitsUsage 
LEFT JOIN (
    SELECT 
     ts.id_baits, 
     COUNT(CASE WHEN e.Status=1 THEN 1 END) AS Undefined, 
     COUNT(CASE WHEN e.Status=1 THEN 1 END) AS GetClose, 
     COUNT(CASE WHEN e.Status=2 THEN 1 END) AS Threat, 
     COUNT(CASE WHEN e.Status=3 THEN 1 END) AS Attack, 
     COUNT(CASE WHEN e.Status=4 THEN 1 END) AS Hooked, 
     COUNT(CASE WHEN e.Status=5 THEN 1 END) AS Captured, 
     COUNT(CASE WHEN e.Status=6 THEN 1 END) AS Tagged, 
     COUNT (*) AS TOTAL 
    FROM CastingsEvents AS e 
    LEFT JOIN Trajectories AS tr ON tr.id = e.id_trajectories 
    LEFT JOIN TimeSegments AS ts ON ts.id = tr.id_timesegments 
    LEFT JOIN Baits AS b ON b.id = ts.Id_Baits 
    GROUP BY ts.id_baits 
) BaitsEvents 
ON BaitsUsage.id_baits=BaitsEvents.id_baits 
ORDER BY bait

來源

2017-10-11 09:23:35 sgm

SQLITE - 合併與伯爵的和sum的兩個表爲一個結果

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