使用Quartz 2D解析pdf時獲得文本位置

Question

關於pdf解析的另一個問題... 只讀閱讀PDF參考版本1.7「5.3.1文本定位運算符」，我有點困惑。

我寫了一些代碼來獲得轉換矩陣和初始文本位置。

 CGPDFOperatorTableSetCallback (table, "MP", &op_MP);//Define marked-content point 
    CGPDFOperatorTableSetCallback (table, "DP", &op_DP);//Define marked-content point with property list 
    CGPDFOperatorTableSetCallback (table, "BMC", &op_BMC);//Begin marked-content sequence 
    CGPDFOperatorTableSetCallback (table, "BDC", &op_BDC);//Begin marked-content sequence with property list 
    CGPDFOperatorTableSetCallback (table, "EMC", &op_EMC);//End marked-content sequence 

    //Text State operators 
    CGPDFOperatorTableSetCallback(table, "Tc", &op_Tc); 
    CGPDFOperatorTableSetCallback(table, "Tw", &op_Tw); 
    CGPDFOperatorTableSetCallback(table, "Tz", &op_Tz); 
    CGPDFOperatorTableSetCallback(table, "TL", &op_TL); 
    CGPDFOperatorTableSetCallback(table, "Tf", &op_Tf); 
    CGPDFOperatorTableSetCallback(table, "Tr", &op_Tr); 
    CGPDFOperatorTableSetCallback(table, "Ts", &op_Ts); 

    //text showing operators 
    CGPDFOperatorTableSetCallback(table, "TJ", &op_TJ); 
    CGPDFOperatorTableSetCallback(table, "Tj", &op_Tj); 
    CGPDFOperatorTableSetCallback(table, "'", &op_apostrof); 
    CGPDFOperatorTableSetCallback(table, "\"", &op_double_apostrof); 

    //text positioning operators   
    CGPDFOperatorTableSetCallback(table, "Td", &op_Td); 
    CGPDFOperatorTableSetCallback(table, "TD", &op_TD); 
    CGPDFOperatorTableSetCallback(table, "Tm", &op_Tm); 
    CGPDFOperatorTableSetCallback(table, "T*", &op_T); 

    //text object operators 
    CGPDFOperatorTableSetCallback(table, "BT", &op_BT);//Begin text object 
    CGPDFOperatorTableSetCallback(table, "ET", &op_ET);//End text object 

因此，這是後應用午餐輸出：

2010-09-02 15:09:23.041 testSearch[8251:207] op_BT begin 
    Integer value: 0 
    2010-09-02 15:09:23.043 testSearch[8251:207] op_BT end 
    2010-09-02 15:09:23.043 testSearch[8251:207] op_Tf begin 
    Integer value: 1 
    2010-09-02 15:09:23.044 testSearch[8251:207] op_Tf end 
    2010-09-02 15:09:23.044 testSearch[8251:207] op_Tm begin 
    Float value: 557.364197 
    2010-09-02 15:09:23.045 testSearch[8251:207] op_Tm end 
    2010-09-02 15:09:23.045 testSearch[8251:207] op_TJ begin 
    2010-09-02 15:09:23.046 testSearch[8251:207] Array string value [0]: F 
    2010-09-02 15:09:23.046 testSearch[8251:207] Array integer value [1]: 94985208 
    2010-09-02 15:09:23.047 testSearch[8251:207] Array string value [2]: r 
    2010-09-02 15:09:23.047 testSearch[8251:207] Array integer value [3]: 94985208 
    2010-09-02 15:09:23.048 testSearch[8251:207] Array string value [4]: o 
    2010-09-02 15:09:23.048 testSearch[8251:207] Array integer value [5]: 94985208 
    2010-09-02 15:09:23.049 testSearch[8251:207] Array string value [6]: m s 
    2010-09-02 15:09:23.049 testSearch[8251:207] Array integer value [7]: 94985208 
    2010-09-02 15:09:23.049 testSearch[8251:207] Array string value [8]: a 
    2010-09-02 15:09:23.050 testSearch[8251:207] Array integer value [9]: 94985208 
    2010-09-02 15:09:23.050 testSearch[8251:207] Array string value [10]: m 
    2010-09-02 15:09:23.051 testSearch[8251:207] Array integer value [11]: 94985208 
    2010-09-02 15:09:23.051 testSearch[8251:207] Array string value [12]: p 
    2010-09-02 15:09:23.052 testSearch[8251:207] Array integer value [13]: 94985208 
    2010-09-02 15:09:23.053 testSearch[8251:207] Array string value [14]: l 
    2010-09-02 15:09:23.054 testSearch[8251:207] Array integer value [15]: 94985208 
    2010-09-02 15:09:23.055 testSearch[8251:207] Array string value [16]: e t 
    2010-09-02 15:09:23.055 testSearch[8251:207] Array integer value [17]: 94985208 
    2010-09-02 15:09:23.057 testSearch[8251:207] Array string value [18]: o r 
    2010-09-02 15:09:23.057 testSearch[8251:207] Array integer value [19]: 94985208 
    2010-09-02 15:09:23.058 testSearch[8251:207] Array string value [20]: e 
    2010-09-02 15:09:23.058 testSearch[8251:207] Array integer value [21]: 94985208 
    2010-09-02 15:09:23.059 testSearch[8251:207] Array string value [22]: s 
    2010-09-02 15:09:23.059 testSearch[8251:207] Array integer value [23]: 94985208 
    2010-09-02 15:09:23.060 testSearch[8251:207] Array string value [24]: u 
    2010-09-02 15:09:23.061 testSearch[8251:207] Array integer value [25]: 94985208 
    2010-09-02 15:09:23.061 testSearch[8251:207] Array string value [26]: l 
    2010-09-02 15:09:23.062 testSearch[8251:207] Array integer value [27]: 94985208 
    2010-09-02 15:09:23.062 testSearch[8251:207] Array string value [28]: t 
    2010-09-02 15:09:23.063 testSearch[8251:207] op_TJ end 

如果有人熟悉文本矩陣和文本定位運營商這將是很好解釋所有的那些事兒工作。

如何使用Tm（變換矩陣和其他數據）計算文本位置（或字形？）？

Answer 1

@科泰：嗨！你終於設法讓它工作？對於Tm，我能夠獲得所有六個值，但現在我看不到如何將一個單詞的位置排成一條線...... 我有一個想法：如果我們在Tj，只是得到字母之間的空格（每次跳轉時都一樣）和Tm，得到一個單詞的位置。在TJ的情況下，這是非常複雜的：獲得水平平移的值以減去Tm矩陣的每個部分的數組，但是搜索該數組中的單詞將比Tj更復雜。

BTW，爲別人的人：

for(size_t n = 0; n < CGPDFArrayGetCount(array); n += 2) 
{ 
    if(n >= CGPDFArrayGetCount(array)) 
     continue; 

    CGPDFStringRef string; 
    success = CGPDFArrayGetString(array, n, &string); 
    if(success) 
    { 
     NSString *data = (NSString *)CGPDFStringCopyTextString(string); 
     NSLog(@"array data : %@", data); 

     [searcher.currentData appendFormat:@"%@", data]; 
     [data release]; 
    } 

    CGPDFReal real; 
    success = CGPDFArrayGetNumber(array, n+1, &real); 
    if(success) 
    { 
     NSLog(@"array real : %f", real); 
    } 
} 

感謝