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我試圖將圖像懸停在圖像上方&。我試圖玩弄CSS的位置,如絕對/相對/固定/靜態。但不知何故,它會出現在桌面上或將桌子推到頁面的底部。定位表格前的懸停圖像
如何將圖像放在我的桌子上方?
CSS:
.searchbutton {
position: relative;
top: 10%;
left: 40%;
display: block;
width: 450px;
height: 450px;
background-image: url('<?php echo $searchpic;?>');
background-repeat:no-repeat;
}
.searchbutton:hover {
position: relative;
top: 10%;
left: 20%;
display: block;
width: 450px;
height: 450px;
background-image: url('<?php echo $searchhoverpic;?>');
background-repeat:no-repeat;
}
PHP:
<?php
include 'database_conn.php';
$sql = "SELECT tablename.ID, tablename.Title, tablename.Year, tablename2.catDesc,tablename.catID
FROM tablename
LEFT JOIN tablename2 ON tablename.catID=tablename2.catID";
$queryresult = mysqli_query($conn, $sql)
or die (mysqli_error($conn));
echo '<table cellpadding="0" cellspacing="0" class="db-table" table align="center">';
echo"<tr><th>Title</th><th>Year</th><th>Category</th> </tr>";
while($row = mysqli_fetch_assoc($queryresult)) {
$iCDID = $row['ID'];
$CDTitle = $row['Title'];
$CDYear = $row['Year'];
$CDCatID = $row['catID'];
echo "<tr><td>";
echo "<div> <a href = \"editCDForm.php?itemCode=$iCDID\">$CDTitle</a> </div>\n";
echo "</td><td>";
echo $row['Year'];
echo "</TD></tr>";
}
echo "</table>";
mysqli_free_result($queryresult);
mysqli_close($conn);
?>
我們會需要與輸出HTML和CSS的演示。 PHP在這裏用處不大。 –
謝謝,我會用css風格來代替......好多了 –