從mysql中給定日期減去天數

Question

個人休假是10天。我需要的剩餘休假從總事假扣除即10天

result i have

SELECT id, firstname,lastname,join_date, completion_date,title, leave_from,leave_to, Given_leave_Days,Taken_Leave_Days,Remaining_Leave_Days FROM (SELECT T1.id,T1.firstname,T1.lastname,T1.join_date,T1.completion_date,T0.title,T2.leave_from,T2.leave_to,T2.user_id,T0.Leave_Days as Given_leave_Days,SUM(DATEDIFF(T2.leave_to,T2.leave_from)+1) AS Taken_Leave_Days ,T0.Leave_Days - SUM(DATEDIFF(T2.leave_to,T2.leave_from)+1) as 'Remaining_Leave_Days' FROM users_leave_request T2 INNER JOIN users T1 ON T2.user_id = T1.id INNER JOIN leave_type T0 ON T2.leave_type_id = T0.id GROUP BY T1.id, T1.firstname, T1.lastname, T1.join_date,T1.completion_date,T0.title,T2.leave_from,T2.leave_to,Given_leave_Days order by firstname) A 

我不得不結果顯示在前端。

result in frontend

Answer 1

一般的答案是

select date_sub(now(), interval 10 day) 

可以更換now()從表中任何日期，可以更改爲daymonth，year等

結果從我示例是今天10天前的日期。例如，如果你只想過濾10天以前的日期，你可以這樣做：

select * from mytable t where t.mydate < date_sub(now(), interval 10 day)