Javascript數組引用

如果我有以下幾點：Javascript數組引用

{"hdrs": ["Make","Model","Year"], 
"data" : [ 
    {"Make":"Honda","Model":"Accord","Year":"2008"} 
    {"Make":"Toyota","Model":"Corolla","Year":"2008"} 
    {"Make":"Honda","Model":"Pilot","Year":"2008"}] 
}

而且我有一個「HDRS」域名（即「做」），我怎麼可以參考data陣列實例？好像data["Make"][0]應該工作...但無法獲得正確的參考

編輯

很抱歉的不確定性。我可以遍歷hdrs讓每個HDR的名字，但我需要使用各實例值hdrs找到data中的所有數據元素（不確定這是否更好解釋）。我會把它在一個變量t，因爲它是JSON（欣賞重新標記），我希望能夠與這樣的引用：t.data[hdrs[i]][j]

來源

2008-09-17 Jay Corbett

你在數據數組中的數組值之間缺少逗號。 – Jared 2008-09-17 19:50:43

非常感謝您的幫助..我改變了帖子的名稱並弄亂了語法，再次感謝 – 2008-09-17 20:40:01

我不得不改變你的代碼一點點：

var x = {"hdrs": ["Make","Model","Year"], 
     "data" : [ 
      {"Make":"Honda","Model":"Accord","Year":"2008"}, 
      {"Make":"Toyota","Model":"Corolla","Year":"2008"}, 
      {"Make":"Honda","Model":"Pilot","Year":"2008"}] 
     }; 

     alert(x.data[0].Make);

編輯：在回答您的編輯

var x = {"hdrs": ["Make","Model","Year"], 
     "data" : [ 
      {"Make":"Honda","Model":"Accord","Year":"2008"}, 
      {"Make":"Toyota","Model":"Corolla","Year":"2008"}, 
      {"Make":"Honda","Model":"Pilot","Year":"2008"}] 
     }; 
var Header = 0; // Make 
for(var i = 0; i <= x.data.length - 1; i++) 
{ 
    alert(x.data[i][x.hdrs[Header]]); 
}

來源

2008-09-17 19:49:56 Jared

也許嘗試數據[0]。使

來源

2008-09-17 19:47:50

關閉，你會用

var x = data[0].Make; 
var z = data[0].Model; 
var y = data[0].Year;

來源

2008-09-17 19:48:18

那麼，像這樣？

var theMap = /* the stuff you posted */; 
var someHdr = "Make"; 
var whichIndex = 0; 
var correspondingData = theMap["data"][whichIndex][someHdr];

這應該工作，如果我理解正確，你......

來源

2008-09-17 19:48:38 Domenic

var x = {"hdrs": ["Make","Model","Year"], 
"data" : [ 
    {"Make":"Honda","Model":"Accord","Year":"2008"} 
    {"Make":"Toyota","Model":"Corolla","Year":"2008"} 
    {"Make":"Honda","Model":"Pilot","Year":"2008"}] 
}; 

x.data[0].Make == "Honda" 
x['data'][0]['Make'] == "Honda"

你有喲ur array/hash lookup backwards :)

來源

2008-09-17 19:50:04

您顯示的代碼在語法上不正確;它需要一些逗號。我得到這個工作：

$foo = {"hdrs": ["Make","Model","Year"], 
"data" : [ 
    {"Make":"Honda","Model":"Accord","Year":"2008"}, 
    {"Make":"Toyota","Model":"Corolla","Year":"2008"}, 
    {"Make":"Honda","Model":"Pilot","Year":"2008"}] 
};

，然後我可以作爲訪問數據：

$foo["data"][0]["make"]

來源

2008-09-17 19:50:36 DGM

感謝您的回覆，您對這些逗號是正確的，我更改了帖子的名稱並搞砸了語法 – 2008-09-17 20:38:35

第一，你忘了你的尾隨逗號數據數組項。

嘗試以下操作：

var obj_hash = { 
    "hdrs": ["Make","Model","Year"], 
    "data" : [ 
     {"Make":"Honda","Model":"Accord","Year":"2008"}, 
     {"Make":"Toyota","Model":"Corolla","Year":"2008"}, 
     {"Make":"Honda","Model":"Pilot","Year":"2008"}, 
    ] 
}; 

var ref_data = obj_hash.data; 

alert(ref_data[0].Make);

@Kent弗雷德裏克：注意最後一個逗號並不是必需的，但可以讓你更輕鬆地左右（移動線即，如果移動或最後一行之後添加，並它沒有逗號，你必須特別記得添加一個，我認爲最好總是有尾隨逗號。）

來源

2008-09-17 19:50:46

我不確定我理解你的問題，但是......

假設上述JSON是VAR OBJ，你想：

obj.data[0]["Make"] // == "Honda"

如果你只是想引用由第一頭所引用的領域，這將是這樣的：

obj.data[0][obj.hdrs[0]] // == "Honda"

來源

2008-09-17 19:50:55 noah

隨着答案的幫助（並得到正確的內外循環之後）我得到這個工作：

var t = eval("(" + request + ")") ; 
for (var i = 0; i < t.data.length; i++) { 
myTable += "<tr>"; 
for (var j = 0; j < t.hdrs.length; j++) { 
    myTable += "<td>" ; 
    if (t.data[i][t.hdrs[j]] == "") {myTable += "&nbsp;" ; } 
    else { myTable += t.data[i][t.hdrs[j]] ; } 
    myTable += "</td>"; 
} 
myTable += "</tr>"; 
}

來源

2008-09-17 20:36:48

Javascript數組引用

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