如何在Bash中傳遞變量作爲參數

Question

我正在嘗試使用osascript腳本更改我的Mac OS X桌面背景。一切工作正常，如果我使用靜態的一切。但是如果我嘗試引入變量，一切都會變得不合時宜。

我的代碼如下。

#! /bin/bash 

function random_wall() 
{ 
    path_name="/Users/Furkan/Pictures/Selection/" 
    my_number=$[RANDOM%$1+1] 
    my_wall="$path_name$2-$my_number.jpg" 
    sec1='tell application "System Events" to set picture of every desktop to ("' 
    sec1+=$my_wall 
    sec2='" as POSIX file as alias)' 
    sec1+=$sec2 
    echo $sec1 
    # This one does not work 
    osascript -e $sec1 
    # The one below works 
    osascript -e 'tell application "System Events" to set picture of every desktop to ("/Users/Furkan/Pictures/Selection/night-3.jpg" as POSIX file as alias)' 
} 

hour=$(date +"%H") 
if [ $hour -ge "5" ] && [ $hour -le "9" ] 
then 
random_wall 8 early-morning 
fi 

if [ $hour -ge "9" ] && [ $hour -lt "13" ] 
then 
random_wall 17 morning 
fi 

if [ $hour -ge "13" ] && [ $hour -lt "17" ] 
then 
random_wall 19 midday 
fi 

if [ $hour -ge "17" ] && [ $hour -lt "20" ] 
then 
random_wall 15 afternoon 
fi 

if [ $hour -ge "20" ] || [ $hour -lt "5" ] 
then 
random_wall 19 night 
fi 

我檢查了輸出。下面的代碼來測試它，靜態文件版本按預期工作。但是，當我嘗試將我的變量作爲參數傳遞時，我收到以下錯誤。

4:4: syntax error: Expected expression but found end of script. (-2741) 

總之，我很困惑如何處理單引號和雙引號的參與。

Answer 1

我剛剛遇到了一個解決方案，我從來沒有想過這會很容易。我需要做的就是用雙引號包裹我的變量名稱。

osascript -e "$sec1"