如何製作不重複輸入兩次的退出方法？

Question

這裏我的問題是，我需要做出退出方法，轉換方法和輸入方法。問題是我不知道如何創建一個退出方法，該方法既包含入口也包含轉換方法值，而不重複兩次。

import java.util.Scanner; 

public class TimeConverter{ 

    public static void main (String[]args){ 
     System.out.println ("This program converts minutes to seconds."); 
     exit(); 
    } 

    public static int entry(){ 
     System.out.print ("\nType in the amount of minutes:"); 
     Scanner s = new Scanner (System.in); 
     int minutes = s.nextInt(); 
     return minutes; 
    } 

    public static int Conversion(){ 
     int val1 = entry(), 
      cont = val1 * 60; 
     return cont; 
    } 

    public static void exit(){ 
     int seconds = conversion(), 
      minutes = entry(); 
     System.out.print ("\n\n" + minutes + " is equal to " + seconds + " seconds."); 
    }  
} 

Answer 1

我將構建main的Scanner，並將它傳遞給entry。接下來，我將返回entry的分鐘數，並將其作爲參數傳遞給conversion方法。最後，通過minutes和seconds至exit。 Like，

public static void main(String[] args) { 
    System.out.println("This program converts minutes to seconds."); 
    Scanner s = new Scanner(System.in); 
    int minutes = entry(s); 
    int seconds = conversion(minutes); 
    exit(minutes, seconds); 
} 

public static int entry(Scanner s) { 
    System.out.println("Type a number of minutes:"); 
    return s.nextInt(); 
} 

public static int conversion(int minutes) { 
    return minutes * 60; 
    // Java also has built-in helpers for this, and you could use 
    // return (int) TimeUnit.MINUTES.toSeconds(minutes); 
} 

public static void exit(int minutes, int seconds) { 
    System.out.printf("%d minutes is equal to %d seconds.%n", minutes, seconds); 
}