python套接字初學者

Question

我知道python，並試圖進入更復雜的東西。我發現這個代碼，它應該可以工作。我收到客戶端第14行的錯誤，返回mrecv ValueError：int（）的基數爲10的無效文字; ''

我有兩個文件分開，然後調用服務器，然後客戶端。當我運行他們的服務器只是說 關閉 和客戶說
recieved->再見!!! 並沒有任何反應，但是當我在客戶端輸入hello時，我得到了上面顯示的錯誤。我可能會/可能做錯了什麼，這是我第一次使用套接字或服務器或其他方法做任何事情。如果你知道我在做什麼錯，請幫忙，如果你有任何其他好的網站或教程對我來說，我將不勝感激。這裏是所有的代碼（不是我）

蟒蛇插座聊天例如， 作者：ANKUR Shrivastava， 許可證：GPL v3的

服務器

import socket 
import threading 
import time 

SIZE = 4 

soc = socket.socket(socket.AF_INET,socket.SOCK_STREAM) 
soc.bind(('127.0.0.1',5432)) 
soc.listen(5) 

class CThread(threading.Thread): 
    def __init__(self,c): 
     threading.Thread.__init__(self) 
     self.conn = c 
     self.stopIt=False 

    def mrecv(self): 
     data = self.conn.recv(SIZE) 
     self.conn.send('OK') 
     msg = self.conn.recv(int(data)) 
     return msg 

    def run(self): 
     while not self.stopIt: 
      msg = self.mrecv() 
      print 'recieved-> ',msg 

def setConn(con1,con2): 
    dict={} 
    state = con1.recv(9) 
    con2.recv(9) 
    if state =='WILL RECV': 
     dict['send'] = con1 # server will send data to reciever 
     dict['recv'] = con2 
    else: 
     dict['recv'] = con1 # server will recieve data from sender 
     dict['send'] = con2 
    return dict 

def msend(conn,msg): 
    if len(msg)<=999 and len(msg)>0: 
     conn.send(str(len(msg))) 
     if conn.recv(2) == 'OK': 
      conn.send(msg) 
    else: 
     conn.send(str(999)) 
     if conn.recv(2) == 'OK': 
      conn.send(msg[:999]) 
      msend(conn,msg[1000:]) # calling recursive 


(c1,a1) = soc.accept() 
(c2,a2) = soc.accept() 
dict = setConn(c1,c2) 
thr = CThread(dict['recv']) 
thr.start() 
try: 
    while 1: 
     msend(dict['send'],raw_input()) 
except: 
    print 'closing' 
thr.stopIt=True 
msend(dict['send'],'bye!!!')# for stoping the thread 
thr.conn.close() 
soc.close() 

客戶

import socket 
import threading 
SIZE =4 
class client(threading.Thread): 
    def __init__(self,c): 
     threading.Thread.__init__(self) 
     self.conn = c 
     self.stopIt = False 

    def mrecv(self): 
     data = self.conn.recv(SIZE) 
     self.conn.send('OK') 
     return self.conn.recv(int(data)) 

    def run(self): 
     while not self.stopIt: 
      msg = self.mrecv() 
      print 'recieved-> ',msg 

soc1 = socket.socket(socket.AF_INET,socket.SOCK_STREAM) 
soc1.connect(('127.0.0.1',5432)) 
soc1.send('WILL SEND') # telling server we will send data from here 

soc2 = socket.socket(socket.AF_INET,socket.SOCK_STREAM) 
soc2.connect(('127.0.0.1',5432)) 
soc2.send('WILL RECV') # telling server we will recieve data from here 

def msend(conn,msg): 
    if len(msg)<=999 and len(msg)>0: 
     conn.send(str(len(msg))) 
     if conn.recv(2) == 'OK': 
      conn.send(msg) 
    else: 
     conn.send(str(999)) 
     if conn.recv(2) == 'OK': 
      conn.send(msg[:999]) 
      msend(conn,msg[1000:]) # calling recursive 
thr = client(soc2) 
thr.start() 
try: 
    while 1: 
     msend(soc1,raw_input()) 
except: 
    print 'closing' 
thr.stopIt=True 
msend(soc1,'bye!!') # for stoping the thread 
thr.conn.close() 
soc1.close() 
soc2.close() 

我嘗試輸入一個數字，它給了我同樣的錯誤。當我從行中取出int並運行客戶端時，它說它必須是一個數字......任何其他想法？

Answer 1

接收器期望4個字節的字符串數據表示要接收的剩餘數據的長度。在這種情況下，前四個字節不包含有效的文本整數（如「1234」），因此對int()的調用失敗。