如何將sql查詢的結果轉換爲csv格式

Question

我的問題很簡單，但我堅持了2周，無法退後一步，看到可能的解決方案。

我有一個SQL查詢看起來像一個結果：

USR Count DATE 
u1  9 160920 
U1  2 160918 
U1  5 160922 
U2  19 160924 
U3  2 160919 
U3  1 160921 
U4  12 160921 

而且我想這個結果轉換爲CSV格式的樣子，使用BASH由於在工作中的服務器上的限制：

;160918;160919;160920;160921;160922;160923;160924 
U1;  2;  0;  9;  0;  5;  0;  0 
U2;  0;  0;  0;  0;  0;  0; 19 
U3;  0;  2;  0;  1;  0;  0;  0 
U4;  0;  0;  0; 12;  0;  0;  0 

我卡住了，我成功地將行轉換爲csv格式，但是當我嘗試在一行中重新組合重複用戶時，我失敗了。

你有任何提示或想法？

Answer 1

SELECT Z.Col1 AS " ", 
     MAX(CASE WHEN Z.Col3 = 160918 THEN Z.Col2 ELSE 0 END) "160918", 
     MAX(CASE WHEN Z.Col3 = 160919 THEN Z.Col2 ELSE 0 END) "160919", 
     MAX(CASE WHEN Z.Col3 = 160920 THEN Z.Col2 ELSE 0 END) "160920", 
     MAX(CASE WHEN Z.Col3 = 160921 THEN Z.Col2 ELSE 0 END) "160921", 
     MAX(CASE WHEN Z.Col3 = 160922 THEN Z.Col2 ELSE 0 END) "160922", 
     MAX(CASE WHEN Z.Col3 = 160923 THEN Z.Col2 ELSE 0 END) "160923", 
     MAX(CASE WHEN Z.Col3 = 160924 THEN Z.Col2 ELSE 0 END) "160924" 
    FROM 
     (
     SELECT * 
      FROM 
     (SELECT 'u1' AS Col1, 9 AS Col2, 160920 AS Col3) UNION ALL 
     (SELECT 'u1' AS Col1, 2 AS Col2, 160918 AS Col3) UNION ALL 
     (SELECT 'u2' AS Col1, 19 AS Col2, 160924 AS Col3) UNION ALL 
     (SELECT 'u3' AS Col1, 2 AS Col2, 160919 AS Col3) UNION ALL 
     (SELECT 'u4' AS Col1, 1 AS Col2, 160921 AS Col3) UNION ALL 
     (SELECT 'u4' AS Col1, 12 AS Col2, 160921 AS Col3) 
     ) Z 
    GROUP BY Z.Col1 
    ORDER BY Z.Col1 
;