油滑3.1.1 sql PSQLException：錯誤：在「」+「或」「附近的語法錯誤」

Question

我有以下簡單（並在Postgres中測試）查詢導致上述錯誤，我無法找到它是什麼。

def findActiveByProviderKeyAndEmail(providerKey: String, email: String): Future[Option[UserRow]] = { 
    val action = sql"""SELECT t1.* FROM user t1 " + 
        "WHERE t1.active=true AND " + 
        "  t1.email=$email AND " + 
        "  EXISTS (SELECT * FROM linked_account t2 " + 
        "    WHERE t2.user_id=t1.id AND " + 
        "     t2.provider_key=$providerKey)""".as[UserRow].headOption 
    db.run(action) 
} 

請注意，我用的是${User.baseTableRow.tableName}代替user和${LinkedAccount.baseTableRow.tableName}代替linked_account但在此之前刪除了排除故障的可能性。

完整的運行時錯誤是：

play.api.http.HttpErrorHandlerExceptions$$anon$1: Execution exception[[PSQLException: ERROR: syntax error at or near "" + 
         "" 
    Position: 26]] 
     at play.api.http.HttpErrorHandlerExceptions$.throwableToUsefulException(HttpErrorHandler.scala:293) 
     at play.api.http.DefaultHttpErrorHandler.onServerError(HttpErrorHandler.scala:220) 
     at play.api.GlobalSettings$class.onError(GlobalSettings.scala:160) 
     at play.api.DefaultGlobal$.onError(GlobalSettings.scala:188) 
     at play.api.http.GlobalSettingsHttpErrorHandler.onServerError(HttpErrorHandler.scala:100) 
     at play.core.server.netty.PlayRequestHandler$$anonfun$2$$anonfun$apply$1.applyOrElse(PlayRequestHandler.scala:100) 
     at play.core.server.netty.PlayRequestHandler$$anonfun$2$$anonfun$apply$1.applyOrElse(PlayRequestHandler.scala:99) 
     at scala.concurrent.Future$$anonfun$recoverWith$1.apply(Future.scala:346) 
     at scala.concurrent.Future$$anonfun$recoverWith$1.apply(Future.scala:345) 
     at scala.concurrent.impl.CallbackRunnable.run(Promise.scala:32) 
Caused by: org.postgresql.util.PSQLException: ERROR: syntax error at or near "" + 
         "" 
    Position: 26 
     at org.postgresql.core.v3.QueryExecutorImpl.receiveErrorResponse(QueryExecutorImpl.java:2455) 
     at org.postgresql.core.v3.QueryExecutorImpl.processResults(QueryExecutorImpl.java:2155) 
     at org.postgresql.core.v3.QueryExecutorImpl.execute(QueryExecutorImpl.java:288) 
     at org.postgresql.jdbc.PgStatement.executeInternal(PgStatement.java:430) 
     at org.postgresql.jdbc.PgStatement.execute(PgStatement.java:356) 
     at org.postgresql.jdbc.PgPreparedStatement.executeWithFlags(PgPreparedStatement.java:168) 
     at org.postgresql.jdbc.PgPreparedStatement.execute(PgPreparedStatement.java:157) 
     at com.zaxxer.hikari.proxy.PreparedStatementProxy.execute(PreparedStatementProxy.java:44) 
     at com.zaxxer.hikari.proxy.PreparedStatementJavassistProxy.execute(PreparedStatementJavassistProxy.java) 
     at slick.jdbc.StatementInvoker.results(StatementInvoker.scala:39) 

Answer 1

你的字符串是錯誤的 - 這裏是一個字符串如何多Scala中完成：https://www.safaribooksonline.com/library/view/scala-cookbook/9781449340292/ch01s03.html

換句話說，它應該是這樣的：

def findActiveByProviderKeyAndEmail(providerKey: String, email: String): Future[Option[UserRow]] = { 
    val action = sql"""SELECT t1.* FROM user t1 
        WHERE t1.active=true AND 
          t1.email=$email AND 
          EXISTS (SELECT * FROM linked_account t2 
            WHERE t2.user_id=t1.id AND 
       t2.provider_key=$providerKey)""".as[UserRow].headOption 
db.run(action) 
}