MySQL的結果插入到數據庫中，但不顯示任何結果

正如標題是，我收到了「主題無法顯示，請稍後再試。」錯誤消息，但數據插入到我的MySQL表罰款，但我不明白爲什麼他們不顯示，這裏是我的結果頁面。MySQL的結果插入到數據庫中，但不顯示任何結果

<?php 
include 'core/init.php'; 
include 'includes/overall/header.php'; 

$sql = "SELECT 'topic_id', 'topic_subject', 'category', 'sub_category', 'posted_by', 'posted', 'view', 'reply' FROM `topics` 
    WHERE topics.topic_id = " . mysql_real_escape_string($_GET['id']); 

$result = mysql_query($sql); 

if(!$result) 
{ 
echo 'The topic could not be displayed, please try again later.'; 
} 
else 
{ 
if(mysql_num_rows($result) == 0) 
{ 
    echo 'This topic doesn&prime;t exist.'; 
} 
else 
{ 
    while($row = mysql_fetch_assoc($result)) 
    { 
     $posts_sql = "SELECT 'posts.post_topic', 'posts.post_content', 'posts.post_date', 'posts.post_by', 
          'users.user_id', 'users.username', 'users.profile' 
       FROM 
        `posts` 
       LEFT JOIN 
        `users` 
       ON 
        posts.post_by = users.user_id 
       WHERE 
        posts.post_topic = " . mysql_real_escape_string($_GET['id']); 

     $posts_result = mysql_query($posts_sql); 

     if(!$posts_result) 
     { 
      echo '<tr><td>The posts could not be displayed, please try again later.</tr></td></table>'; 
     } 
     else 
     { 

      while($posts_row = mysql_fetch_assoc($posts_result)) 
      { 
       include("includes/results-template.php"); 

      } 
     } 

     if(!$_SESSION['signed_in']) 
     { 
      echo '<tr><td colspan=2>You must be <a href="signin.php">signed in</a> to reply. You can also <a href="signup.php">sign up</a> for an account.'; 
     } 
     else 
     { 
      //show reply box 
      echo '<tr><td colspan="2"><h2>Reply:</h2><br /> 
       <form method="post" action="reply.php?id=' . $row['topic_id'] . '"> 
        <textarea name="reply-content"></textarea><br /><br /> 
        <input type="submit" value="Submit reply" /> 
       </form></td></tr>'; 
     } 

     //finish the table 
     echo '</table>'; 
    } 
} 
} 
?> 
<?php include 'includes/overall/footer.php'; ?>

來源

2013-07-13 user2571547

您不能選擇帶單引號的列，而應該使用反引號選擇它們。

查詢更改爲

$sql = "SELECT `topic_id`, `topic_subject`, `category`, `sub_category`, `posted_by`, `posted`, `view`, `reply` FROM `topics` 
WHERE topics.topic_id = '".mysql_real_escape_string($_GET['id'])."' ";

而且這種查詢$posts_sql更改爲：

 $posts_sql = "SELECT posts.post_topic, posts.post_content, posts.post_date, posts.post_by, users.user_id, users.username, users.profile 
      FROM 
       `posts` 
      LEFT JOIN 
       `users` 
      ON 
       posts.post_by = users.user_id 
      WHERE 
       posts.post_topic = '" . mysql_real_escape_string($_GET['id'])."' ";

有反引號之間的不同`和單引號'。

來源

2013-07-13 12:17:02

MySQL的結果插入到數據庫中，但不顯示任何結果

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