無法在Python3中創建列表的淺表副本

我正在嘗試實現一個簡單的TicTacToe遊戲，但我無法制作某個列表的淺表副本。雖然我給你新的價值只體現在SIM卡中，變化體現在「主」板無法在Python3中創建列表的淺表副本

SIZE = 3 # size of game board 
PLAYERS = (PLAYER, COMPUTER) = "X", "O" 

class TicTacToe(list): 
    """ Class handling game board """ 
    def __init__(self, size=SIZE, players=PLAYERS): 
     """ Board size defaults to 3 """ 
     super().__init__([[" " for idx in range(size)] for jdx in range(size)]) 
     self._size = size 

    def winner_move(self, letter, range_): 
     """ Determine winner move - range_ members are tuples """ 
     for tile in range_: 
      sim = self[:] # shallow copy of game board for simulation 
      sim[tile[0]][tile[1]] = letter 
      print("Current board:") 
      print(self) 
      # code makes some decisions here and continues 

    def get_empty(self): 
     """ Return empty places on board as a set of (row, col) """ 
     return {(row, col) for row in range(self._size)\ 
       for col in range(self._size) if self[row][col] == " "} 

board = TicTacToe() 
board.winner_move(PLAYER, board.get_empty())

：下面是我的腳本最小提取物，呈現我的問題。我也試過

sim = list(self)

和

sim = [item for item in self]

但都給予同樣的結果。

任何建議我做錯了什麼？

來源

2016-01-22 rolika

TicTacToe是一個2D結構，你真的需要淺而不深的複製？ – Arpegius

@Arpegius是賴特，你需要深刻的複製 –

Arpegius' comment是對的。你有一個嵌套列表。使用sim = self[:],sim = list(self)或sim = [item for item in self]，您會得到一個新的外部列表，但它將成爲與內部列表相同的列表。

sim = [lst[:] for lst in self]

或

sim = [list(lst) for lst in self]

會工作，但

from copy import deepcopy 
# ... 
sim = deepcopy(self)

更優雅，其目的是更容易理解。見its documentation。

來源

2016-01-22 21:41:57

謝謝你們，我從你身上學到了很多東西:-) – rolika

無法在Python3中創建列表的淺表副本

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