JavaScript函數以下可用於檢查所有子節點,如果家長檢查,檢查父節點,如果至少一個子節點,否則檢查是未選中:
function OnTreeClick(evt) {
var src = window.event != window.undefined ? window.event.srcElement : evt.target;
var isChkBoxClick = (src.tagName.toLowerCase() == "input" && src.type == "checkbox");
var t = GetParentByTagName("table", src);
if (isChkBoxClick) {
var parentTable = GetParentByTagName("table", src);
var nxtSibling = parentTable.nextSibling;
if (nxtSibling && nxtSibling.nodeType == 1) {
if (nxtSibling.tagName.toLowerCase() == "div") {
CheckUncheckChildren(parentTable.nextSibling, src.checked);
}
}
CheckUncheckParents(src, src.checked);
}
}
function CheckUncheckChildren(childContainer, check) {
var childChkBoxes = childContainer.getElementsByTagName("input");
var childChkBoxCount = childChkBoxes.length;
for (var i = 0; i < childChkBoxCount; i++) {
childChkBoxes[i].checked = check;
}
}
function CheckUncheckParents(srcChild, check) {
var parentDiv = GetParentByTagName("div", srcChild);
var parentNodeTable = parentDiv.previousSibling;
if (parentNodeTable) {
var checkUncheckSwitch;
var isAllSiblingsChecked = AreAllSiblingsChecked(srcChild);
if (isAllSiblingsChecked) {
checkUncheckSwitch = true;
}
else {
checkUncheckSwitch = false;
}
var inpElemsInParentTable = parentNodeTable.getElementsByTagName("input");
if (inpElemsInParentTable.length > 0) {
var parentNodeChkBox = inpElemsInParentTable[0];
parentNodeChkBox.checked = checkUncheckSwitch;
CheckUncheckParents(parentNodeChkBox, checkUncheckSwitch);
}
}
}
function AreAllSiblingsChecked(chkBox) {
var parentDiv = GetParentByTagName("div", chkBox);
var childCount = parentDiv.childNodes.length;
var k = 0;
for (var i = 0; i < childCount; i++) {
if (parentDiv.childNodes[i].nodeType == 1) {
if (parentDiv.childNodes[i].tagName.toLowerCase() == "table") {
var prevChkBox = parentDiv.childNodes[i].getElementsByTagName("input")[0];
//if any of sibling nodes are not checked, return false
if (prevChkBox.checked) {
//add each selected node one value
k = k + 1;
}
}
}
}
//Finally check any one of child node is select if selected yes then return ture parent node check
if (k > 0) {
return true;
}
else {
return false;
}
}
function GetParentByTagName(parentTagName, childElementObj) {
var parent = childElementObj.parentNode;
while (parent.tagName.toLowerCase() != parentTagName.toLowerCase()) {
parent = parent.parentNode;
}
return parent;
}
我用這個javascript來解決我的問題。
嗨,感謝您的回覆.i嘗試了您的代碼,但發生錯誤,如錯誤'admin_Add_Role.checkTreeNodes(System.Web.UI.WebControls.TreeNodeCollection,bool)'的最佳重載方法匹配有一些無效參數\t錯誤參數1:無法從'方法組'轉換爲'System.Web.UI.WebControls.TreeNodeCollection' – Amritha 2012-07-25 04:59:07
checkTreeNodes,如您在函數中所看到的那樣,將TreeNodeCollection作爲參數。你的錯誤表明你將它傳遞給你的樹的TreeNodeCollection。 – nunespascal 2012-07-25 05:05:00