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我有一個項目供我上學的學校使用。我們必須劃分兩個數字,並顯示答案和餘數。該值在函數內是正確的,但是當我試圖通過main函數傳遞它時,它給了我錯誤的數字。感謝您的幫助項目幫助 - 無法通過函數傳遞值
#include <stdio.h>
void division (int number, int divisor, int *quotient, int *remainder);
int main(void)
{
int i, d, q, r;
int *quotient = &q;
int *remainder = &r;
printf("Enter an integer and divisor, separated by comma: ");
scanf("%d, %d", &i, &d);
division(i, d, quotient, remainder);
printf("%d divided by %d: quotient = %d, remainder = %d\n", i, d,
*quotient, *remainder);
return 0;
}
void division(int number, int divisor, int *quotient, int *remainder)
{
int a = number/divisor;
printf(" a = %d\n", a);
int b = number % divisor;
printf(" b = %d\n", b);
quotient = *a;
remainder = *b;
}
'quotient = * a; remaining = * b;' - >'* quotient = a; *餘數= b;' – BLUEPIXY
該代碼不能編譯 - 或者不應該編譯。 'a'由於'a'不是指針而無效。 –