我正在編寫一個程序,定期啓動一個服務的意圖,要做到這一點我已經決定使用alarmmanager,我能夠做到這一點,我想在一個活動相當容易,但林試圖時,我會得到一個錯誤在我無法弄清楚的接收器中做到這一點。使用廣播接收器在Android中啓動AlarmManager?
AlarmManager am = (AlarmManager)getSystemService(ALARM_SERVICE);
告訴我,ALARM_SERVICE不能被解析爲一個變量
這是我爲reciever完整代碼:
package com.testapp21.second.activities;
import android.app.AlarmManager;
import android.app.PendingIntent;
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.os.SystemClock;
public class PhoneOnReceiver extends BroadcastReceiver {
private PendingIntent mAlarmSender;
@Override
public void onReceive(Context context, Intent intent) {
mAlarmSender = PendingIntent.getService(context,
0, new Intent(context, StatsCheckerService.class), 0);
// We want the alarm to go off 30 seconds from now.
long firstTime = SystemClock.elapsedRealtime();
// Schedule the alarm!
AlarmManager am = (AlarmManager)getSystemService(ALARM_SERVICE);
am.setRepeating(AlarmManager.ELAPSED_REALTIME_WAKEUP,
firstTime, 30*1000, mAlarmSender);
}
}
當你說「ALARM_SERVICE不能解析爲變量」你的意思是你在運行時得到一個異常或什麼? – Rasive 2012-03-07 14:24:53
它在編譯器中有一個紅色下劃線的錯誤,我認爲它與廣播接收器中的上下文有所不同,但我不知道如何修復它 – 2012-03-07 14:29:34