如何使用日期時間

Question

獲得Python中的某一天的下月的同一天，我知道使用datetime.timedelta我可以得到一些天遠形式給出日期

daysafter = datetime.date.today() + datetime.timedelta(days=5) 

日期，但似乎沒有日期時間。 timedelta（月= 1）

！感謝您的幫助！

Answer 1

當然沒有 - 如果今日1月31日，這將是「下個月的同一天」？顯然沒有對的解決方案，因爲2月31日不存在，而datetime模塊確實不是發揮在「猜測什麼用戶提出這個不可能的問題沒有一個正確的解決方案認爲（錯誤）是明顯的解決方案」; - ）。

我建議：

try: 
    nextmonthdate = x.replace(month=x.month+1) 
except ValueError: 
    if x.month == 12: 
    nextmonthdate = x.replace(year=x.year+1, month=1) 
    else: 
    # next month is too short to have "same date" 
    # pick your own heuristic, or re-raise the exception: 
    raise 

Answer 2

使用dateutil模塊。它有relative time deltas：

import datetime 
from dateutil import relativedelta 
nextmonth = datetime.date.today() + relativedelta.relativedelta(months=1) 

美麗。

Answer 3

from calendar import mdays 
from datetime import datetime, timedelta 

today = datetime.now() 
next_month_of_today = today + timedelta(mdays[today.month]) 

我不想導入dateutil。試試這個。祝你好運。

Answer 4

import calendar, datetime 

def next_month (date): 
    """return a date one month in advance of 'date'. 
    If the next month has fewer days then the current date's month, this will return an 
    early date in the following month.""" 
    return date + datetime.timedelta(days=calendar.monthrange(date.year,date.month)[1]) 

Answer 5

from datetime import timedelta 
try: 
    next_month = (x.replace(day=28) + timedelta(days=7)).replace(day=x.day) 
except ValueError: # assuming January 31 should return last day of February. 
    next_month = (x + timedelta(days=31)).replace(day=1) - timedelta(days=1) 

Answer 6

這是我如何解決它。

from datetime import date 
try: 
    (year, month) = divmod(date.today().month, 12) 
    next_month = date.today().replace(year=date.today().year+year, month=month+1) 
except ValueError: 
    # This day does not exist in next month 

可以跳過try/catch語句，如果你只通過設置replace(year=date.today().year+year, month=month, day=1)想的第一天下個月。這將永遠是因爲我們已經趕上使用divmod月份溢出有效日期。

Answer 7

這項工作對我來說

import datetime 
import calendar 


def next_month_date(d): 
    _year = d.year+(d.month//12) 
    _month = 1 if (d.month//12) else d.month + 1 
    next_month_len = calendar.monthrange(_year,_month)[1] 
    next_month = d 
    if d.day > next_month_len: 
     next_month = next_month.replace(day=next_month_len) 
    next_month = next_month.replace(year=_year, month=_month) 
    return next_month 

用法：

d = datetime.datetime.today() 
print next_month_date(d)