我已經閱讀了大量類似的問題,但沒有找到答案。我正在使用Visual Studio 2010並提升1.47。派生對象的boost序列化不調用派生的序列化()
下面的代碼,它是完整的,可編譯:
#include "stdafx.h"
#include <string>
#include <sstream>
#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>
#include <boost/serialization/export.hpp>
using namespace std;
class BaseObject
{
public:
BaseObject(void) { };
virtual ~BaseObject(void) { };
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{ /* nothing happens here */ };
};
class DerivedObject : public BaseObject
{
public:
string text;
public:
DerivedObject(void) { };
~DerivedObject(void) { };
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{
ar & text;
};
};
BOOST_CLASS_EXPORT(DerivedObject)
int _tmain(int argc, _TCHAR* argv[])
{
DerivedObject der;
der.text = "Testing!";
std::ostringstream os;
boost::archive::text_oarchive oa(os);
oa.register_type<DerivedObject>();
// I made a DerivedObject, but I'm casting it to a BaseObject
// as the serialization code should not have to know what type it is
BaseObject *base = &der;
// now serialize it
oa << *base;
printf("serialized: %s\r\n",os.str().c_str());
return (0);
}
你可以看到它的真正簡單,我添加了是應該確保DerivdObject ::序列化BOOST_CLASS_EXPORT和oa.register_type魔術()被稱爲即使它不是一個虛擬的方法..但仍然只調用BaseObject中的serialize()。一個特定於Visual C++的問題?請指教?
不應該將'BaseObject :: serialize'標記爲'virtual'? – Nick 2012-03-15 10:45:25
不,它是一個模板,它不可能 – 2012-03-15 10:50:41
好點 - 沒有注意到模板位! – Nick 2012-03-15 10:53:46