BeautifulSoup的FindAll「名單」對象有沒有屬性「find_all」

Question

from bs4 import BeautifulSoup 
from pprint import pprint 
import requests 

url = "http://chk.tbe.taleo.net/chk01/ats/careers/searchResults.jsp?org=CDI&cws=1" 

response = requests.get(url) 

soup = BeautifulSoup(response.text, "html.parser") 

table_main = soup.select("table#cws-search-results") 

table = table_main.find_all("tr") 

for tr in table: 
    job_title = tr.find_all("a") 
    job_location = tr.find_all("b") 

    job = { 
     "job_title": job_title, 
     "job_location": job_location 
    } 
    data.append(job) 

pprint(jobs) 

Answer 1

因爲soup.select("table#cws-search-results")是返回Tag對象（在這種情況下，1項列表）的列表，你得到一個錯誤，而不是一個單一的Tag對象， find_all是Tag對象不是Python list對象的方法。

變化：

table_main = soup.select("table#cws-search-results") 

到：

table_main = soup.select_one("table#cws-search-results") 

得到Tag對象表示主表，然後在該對象上調用find_all會正常運行。