fvctl命令的解釋？

Question

我真的需要你的幫助來了解什麼dl_type = 0x0800的和nw_proto = 6意味着flowvisor的這個命令：

$ fvctl -f /開發/空附加流動空間dpid1-接口4視頻-src 1 100 in_port = 4，dl_type = 0x0800，nw_proto = 6，tp_src = 9999 video = 7

謝謝！

Answer 1

約定與Open vSwitch ovs-ofctl工具相同，該聯機幫助頁包含您正在查找的所有信息。

該手冊頁的純文本版本可以找到here。

它提到：

The following shorthand notations are also available: 
(...) 
tcp Same as dl_type=0x0800,nw_proto=6. 
(...) 

完整的描述有更多的信息：

dl_type=ethertype 
      Matches Ethernet protocol type ethertype, which is specified as 
      an integer between 0 and 65535, inclusive, either in decimal or 
      as a hexadecimal number prefixed by 0x (e.g. 0x0806 to match ARP 
      packets). 

nw_proto=proto 
ip_proto=proto 
      When ip or dl_type=0x0800 is specified, matches IP protocol type 
      proto, which is specified as a decimal number between 0 and 255, 
      inclusive (e.g. 1 to match ICMP packets or 6 to match TCP pack‐ 
      ets). 

      When ipv6 or dl_type=0x86dd is specified, matches IPv6 header 
      type proto, which is specified as a decimal number between 0 and 
      255, inclusive (e.g. 58 to match ICMPv6 packets or 6 to match 
      TCP). The header type is the terminal header as described in 
      the DESIGN document. 

      When arp or dl_type=0x0806 is specified, matches the lower 8 
      bits of the ARP opcode. ARP opcodes greater than 255 are 
      treated as 0. 

      When rarp or dl_type=0x8035 is specified, matches the lower 8 
      bits of the ARP opcode. ARP opcodes greater than 255 are 
      treated as 0. 

      When dl_type is wildcarded or set to a value other than 0x0800, 
      0x0806, 0x8035 or 0x86dd, the value of nw_proto is ignored (see 
      Flow Syntax above).